what is the specific heat of a substance that requires 99,100J of thermal energy to heat 3.47 kg of this substance from 15 C to
1 answer:
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Answer:
The work done on the box is 80 J.
Explanation:
Given that,
Weight of box = 40 N
Distance = 2 meter
We need to calculate the work done
Using formula of work done
Where, x = distance
mg = weight
Put the value into the formula
Hence, The work done on the box is 80 J.
The vector, the x-component and the y-component form a rectangle triangle where the vector is the hypothenuse and the x and y components are the two sides.
Calling
the angle between the vector and the horizontal direction (x), the two sides are related to by
where vy and vx are the two components on the y- and x-axis. Using vx=10 and vy=3 we find
And so the angle is
Calling
where vy and vx are the two components on the y- and x-axis. Using vx=10 and vy=3 we find
And so the angle is