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Mumz [18]
3 years ago
15

what is the specific heat of a substance that requires 99,100J of thermal energy to heat 3.47 kg of this substance from 15 C to

41C​
Physics
1 answer:
Nady [450]3 years ago
7 0

Answer:

1098.42 J/kg.c°

Explanation:

Q=mcT

you have : Q = 99100

m=3.47kg

and the change in temperature T = 41-15=26c°

Solve for specific heat c :

c = Q/mT === 99100/3.47(26) = 1098.42J/kg . c°

I hope that it's a clear solution and explanation.

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Answer:

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Explanation:

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Where i and f stands for initial and final states of each energy component.

Hence, the right answer is K_{i}+U_{g,i} = K_{f}+U_{g,f}

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3 years ago
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Answer:

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<span>The answer is C. A scale would include a series of eight notes, where the first and seventh notes have the same letter.

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scZoUnD [109]

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Explanation:

Given

The slits are separated by d=0.510\ mm

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Also, the distance between bright fringes is given by  

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