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arsen [322]
3 years ago
8

Two groups wanted to determine which size of parachute, when released, fell to the ground the slowest. Each group's design and r

esults are shown in the table below.
Each group designed their parachutes as follows:
Design and Results by Group

Group 1
6 20 cm pieces of string
1 50 g package
24 cm round plastic parachute

Results
6 seconds
Group 2
6 20 cm pieces of string
1 50 g package
12 cm round plastic parachute

Results
3 seconds

Which of the following explains why this exercise represents a carefully designed experiment?

A.
They used the same mass of package in all the trials.
B.
They altered only one variable in their design and testing.
C.
They used the same materials when making each parachute.
D.
They confirmed that the smaller the parachute, the faster it falls.
Physics
1 answer:
ser-zykov [4K]3 years ago
3 0
The correct answer is B) They altered only one variable in their design and testing.
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Hybrid

<u>Hybrid</u> modified the concept by adding an internal combustion engine and marketing hybrids that were part electric and part gas powered.

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3 0
2 years ago
If time travel to the future existed, doesn't that mean that the future has already occurred and that we are living in the past?
kodGreya [7K]

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Explanation:

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3 years ago
A mass is attached to a spring with an unknown spring constant. The spring gains 10 J of elastic potential energy if stretched b
Firlakuza [10]

From the given information in the question, the correct option is Option 1: 14 cm.

A non-stretched elastic spring has a conserved potential energy which gives it the ability to perform work. The elastic potential energy can be expressed as:

PE = \frac{1}{2} k x^{2}

Where PE is the energy, k is the spring constant and x is extension.

i. Given that: PE = 10 J and x = 10 cm, then;

PE = \frac{1}{2} k x^{2}

10 = \frac{1}{2} k 10^{2}

20 = 100k

k = 0.2 J/cm

ii. To determine how far the spring is needed to be stretched, given that PE = 20 J.

PE = \frac{1}{2} k x^{2}

20 = \frac{1}{2} (0.2) x^{2}

40 = 0.2 x^{2}

x^{2} = 200

x = \sqrt{200}

  = 14.1421

x = 14.14 cm

So that;

x is approximately 14.00 cm.

Thus, the spring need to be stretched to 14.00 cm to give the spring 20 J of elastic potential energy.

For more information, check at: brainly.com/question/1352053.

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About how much of the United States' electricity is produced by nuclear reactors?​
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Answer:

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