Answer:
1.87 A
Explanation:
τ = mean time between collisions for electrons = 2.5 x 10⁻¹⁴ s
d = diameter of copper wire = 2 mm = 2 x 10⁻³ m
Area of cross-section of copper wire is given as
A = (0.25) πd²
A = (0.25) (3.14) (2 x 10⁻³)²
A = 3.14 x 10⁻⁶ m²
E = magnitude of electric field = 0.01 V/m
e = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C
m = mass of electron = 9.1 x 10⁻³¹ kg
n = number density of free electrons in copper = 8.47 x 10²² cm⁻³ = 8.47 x 10²⁸ m⁻³
= magnitude of current
magnitude of current is given as


= 1.87 A
Answer:
= 2
Explanation:
During nuclear fusion, two lighter nuclei of elements combine to form heavy nucleus and also energy is released;
During the process of hydrogen fusion a nucleus of deuterium is formed from two protons with emission of a neutrino.
In this case deuterium fuses with hydrogen nuclei to form helium-3 and also release energy.
That is;
2/1 H + 1/1 H = 3/1 He + energy
The relationship between electricity and magnetism is called<span> electromagnetism.</span>
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