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arsen [322]
3 years ago
8

Two groups wanted to determine which size of parachute, when released, fell to the ground the slowest. Each group's design and r

esults are shown in the table below.
Each group designed their parachutes as follows:
Design and Results by Group

Group 1
6 20 cm pieces of string
1 50 g package
24 cm round plastic parachute

Results
6 seconds
Group 2
6 20 cm pieces of string
1 50 g package
12 cm round plastic parachute

Results
3 seconds

Which of the following explains why this exercise represents a carefully designed experiment?

A.
They used the same mass of package in all the trials.
B.
They altered only one variable in their design and testing.
C.
They used the same materials when making each parachute.
D.
They confirmed that the smaller the parachute, the faster it falls.
Physics
1 answer:
ser-zykov [4K]3 years ago
3 0
The correct answer is B) They altered only one variable in their design and testing.
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3 years ago
Which of the following exhibit the Tyndall Effect?
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Answer:

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8 0
2 years ago
To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.7 kg and length 3.0 m
Zanzabum

Answer:

T_{1} = 14.88 N

Explanation:

Let's begin by listing out the given variables:

M = 2.7 kg, L = 3 m, m = 1.35 kg, d = 0.6 m,

g = 9.8 m/s²

At equilibrium, the sum of all external torque acting on an object equals zero

τ(net) = 0

Taking moment about T_{1} we have:

(M + m) g * 0.5L - T_{2}(L - d) = 0

⇒ T_{2} = [(M + m) g * 0.5L] ÷ (L - d)

T_{2} = [(2.7 + 1.35) * 9.8 * 0.5(3)] ÷ (3 - 0.6)

T_{2}= 59.535 ÷ 2.4

T_{2} = 24.80625 N ≈ 24.81 N

Weight of bar(W) = M * g = 2.7 * 9.8 = 26.46 N

Weight of monkey(w) = m * g = 1.35 * 9.8 = 13.23 N

Using sum of equilibrium in the vertical direction, we have:

T_{1} + T_{2} = W + w   ------- Eqn 1

Substituting T2, W & w into the Eqn 1

T_{1} + 24.81 = 26.46 + 13.23

T_{1} = <u>14.88</u> N

8 0
2 years ago
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