The magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.
<h3>Impulse experienced by objects</h3>
The impulse experienced by any object is equal to the change in the momentum of the object.
The magnitude of the impulse delivered to the baseball by the bat is calculated by applying the following equation.
J = Ft
where;
- F is applied force = 8000 N
- t is time, = 1.1 ms
J = (8000) x (1.1 x 10⁻³)
J = 8.8 Ns
Thus, the magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.
Learn more about impulse here: brainly.com/question/229647
Answer:
-3.4 m
Explanation:
The displacement is the difference between the final position and the initial position:
4.4 m - 7.8 m = -3.4 m
Answer:
the string and metre rule
Explanation:
Answer:
your velocity is 2.5 m/sec
Answer:
v= 13 m/s
Explanation:
Velocity is defined as the derivative of displacement with respect to time
v= ds/dt
Known data
s(t) = 5t + 2t² : distance that the ball has rolled after t seconds
vi= 5 m/s : initial velocity
t= 2 s
Problem develoment
s(t) = 5t + 2t²
v= ds/dt= 5 + 4t : velocity of the ball in function of the time
We replace t =2 s in the equation of velocity
v= 5 + 4(2)
v= 13 m/s : velocity after 2 seconds
