Answer:
Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
Answer:
The answer is -7
Step-by-step explanation:
I took the test! Hope this helps <3
The answer is 1 over 3(3.14)(5²)(8)
The volume of the cylinder (V1) is:
V1 = π · r² · h (r - radius, h - height)
The volume of the cone (V2) is:
V2 = 1/3 π · r² · h (r - radius, h - height)
It is given:
r = 5 feet
h = 8 feet
π = 3.14
Therefore, the volume of the cone is:
V2 = 1/3 · 3.14 · 5² · 8 which is the same as 1 over 3(3.14)(5²)(8).
The numbers are being multiplied by 7
.5 • 7 = 3.5
3.5 • 7 = 24.5
24.5 • 7 = 171.5
etc
