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The liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas and hydrogen gas are
When liquid disilicon hexachloride reacts with water to form solid silicon dioxide , hydrogen chloride gas and hydrogen gas , the following chemical equation is:
now , we have to balance the eqaution,
Reactants product
Si 2 1
Cl 6 1
H 2 3
O 1 2
Multiply 4 with 
2 with 
and 6 with HCL, we get
now ,
Reactant Product
Si 2 2
Cl 6 6
H 8 8
O 4 4
Thus, we get the desire equtions.
The liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas and hydrogen gas are
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Answer:
HCl is not a catalyst because these are not used up during the chemical reactions.
Explanation:
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In this case, according to the performed experiments, it is possible for us to realize that HCl cannot be a catalyst for this reaction because it is used up during the reaction. This is explained by the fact that catalyst are able to return to the original form once the reaction has gone to completion; this is the example of palladium in the hydrogenation or dehydrogenation of hydrocarbons depending on the case. Moreover, we know that the catalysts increase the reaction rate because they decrease the activation energy of the reaction and therefore the student observed such increase.
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Answer:
the best estimate is 34.69 g
Explanation:
the best estimate is 34.69 gm because when it is rounded it becomes 34.70 gm which is near to actual weight 34.75 gms
Answer:
160 g of NaOH
Explanation:
Reaction: 2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O
When a base and an acid react, the produce water and a salt. → Neutralization
In this reaction 2 moles of hydroxide need 1 mol of sulfuric acid to react, it is the same to say that 1 mol of sulfuric acid needs 2 moles of NaOH to react. We convert the mass of sulfuric to moles and we propose the rule of three:
196 g / 98 g/mol = 2 moles
1 mol of sulfuric acid needs 2 moles of NaOH to react
Then 2 moles of sulfuric acid will react with (2 . 2) /1 = 4 moles of NaOH
We convert the moles of base to grams → 4 mol . 40 g /1mol = 160 g
