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Alik [6]
3 years ago
7

how many moles of zinc cholride are produced from the reaction of three moles of xinc and an excess of hydrocholric acid

Chemistry
1 answer:
Leno4ka [110]3 years ago
4 0
The answer is 3 moles  as per given balanced equation one mole Zn produces 1mole Hydrogen
when reacted with excess acid.
<span>So 3 moles Zn will give 3moles Hydroge</span> 
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Which of the following statements below correctly describes the parts of an atom that determine the atom's identity and chemical
stich3 [128]

Answer:

B protons determine indentity and valence electrons determine chemical properties.

:)

Explanation:

6 0
3 years ago
Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e
notsponge [240]

<u>Answer:</u> The concentration of Sn^{2+} in the cell is 9.0\times 10^{-3}M

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u>  Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-   E^o_{Zn^{2+}/Zn}=-0.76V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)   E^o_{Sn^{2+}/Sn}=-0.136V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.136-(-0.76)=0.624V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}

where,

E_{cell} = electrode potential of the cell = 0.660 V

E^o_{cell} = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

[Zn^{2+}]=2.5\times 10^{-3}M

[Sn^{2+}] = ?

Putting values in above equation, we get:

0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})

[Sn^{2+}]=9.0\times 10^{-3}M

Hence, the concentration of Sn^{2+} ions is 9.0\times 10^{-3}M

3 0
3 years ago
Which of the following would be a warning sign that information about a weight loss medication is not reliable science?
Helga [31]

Answer:

c

Explanation:

I think it is right not sure but hope it helped

5 0
3 years ago
What is the molality of a solution of water and KCl if the freezing point of the solution is –3°C? (Kf = 1.86°C/m; molar mass of
Elina [12.6K]
Some of the solutions exhibit colligative properties. These properties depend on the amount of solute dissolved in a solvent. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering. Calculations are as follows:

<span> ΔT(freezing point)  = (Kf)mi
3  = 1.86 °C kg / mol (m)(2)
3 =3.72m
m = 0.81 mol/kg</span>

4 0
3 years ago
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A student had a sample of pure water, and added an unknown substance to it. The student noticed that the hydroxide ion concentra
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The answer is A it's a basic because once you add another substance to a neutral it either becomes acidic or basic. this one becomes basic because the hydroxide ion concentrate increased.
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3 years ago
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