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Orlov [11]
3 years ago
12

According to the following reaction, how many grams of sulfur are formed when 37.4 g of water are formed?

Chemistry
1 answer:
julia-pushkina [17]3 years ago
8 0

Answer:

Mass = 100.8 g

Explanation:

Given data:

Mass of sulfur formed = ?

Mass of water formed = 37.4 g

Solution:

Chemical equation:

2H₂S + SO₂      →   3S + 2H₂O

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 37.4 g/ 18 g/mol

Number of moles = 2.1 mol

Now we will compare the moles of water and sulfur.

          H₂O         :            S

            2             :          3

           2.1            :         3/2×2.1 = 3.15

Mass of sulfur:

Mass = number of moles × molar mass

Mass = 3.15 mol × 32 g/mol

Mass = 100.8 g

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Answer:

1 - 3

Explanation:

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- Hope this helped! If you need a further explanation please let me know.

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Explanation:

5 0
2 years ago
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According to the Law of Conservation of Mass, how much water is produced if 22.5 g of
nadezda [96]

Answer: The amount of water produced is 9.3 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CH_4+2O_2\rightarrow CO_2+2H_2O

mass of reactants = mass of methane + mass of oxygen = 22.5 g + 35.7 g = 58.2 g

mass of products = mass of carbon dioxide + mass of water = 48.9 g +  mass of water

48.9 g +  mass of water = 58.2 g

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4 0
3 years ago
What is the pressure of 1.50 moles of a gas in a 30.0L tank at a temperature of<br> 285K?
julia-pushkina [17]

The pressure of the gas : 1.1685 atm

<h3>Further explanation</h3>

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

n=moles=1.5

V=volumes = 30 L

T=temperature=285 K

The pressure :

\tt P=\dfrac{nRT}{V}\\\\n=\dfrac{1.5\times 0.082\times 285}{30}\\\\P=1.1685~atm

7 0
2 years ago
Match the following numbers with the correct number of significant digits they possess. Answers may repeat. (4 points)
mezya [45]

(B. 3) 172 All nonzero digits are significant.

(A. 4) 450.0 x 10^3 Trailing zeroes after the decimal point are significant.

(A. 4) 3427 All nonzero digits are significant.

(B. 3) 0.0000455 Leading zeroes are not significant.

(B. 3) 0.00456 Leading zeroes are not significant.

(C. 5) 2205.2 Zeroes between nonzero digits are significant.

(C. 5) 107.20 Trailing zeroes after the decimal point are significant.

(B. 3) 0.0473 Leading zeroes are not significant.

8 0
3 years ago
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