Steel is an alloy that is mainly comprised of CARBON. Hope this helps and give thanks plsss!
5= chemicals
6= hormones
Don't know the other ones.
Answer:
The final pressure of the gas is 370. kPa
Explanation:
Let's assume the gas inside cylinder behaves ideally.
As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-
![\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7B1%7DV_%7B1%7D%7D%7BT_%7B1%7D%7D%3D%5Cfrac%7BP_%7B2%7DV_%7B2%7D%7D%7BT_%7B2%7D%7D)
where
and
are initial and final pressure respectively.
and
are initial and final volume respectively.
and
are initial and final temperature in kelvin scale respectively.
Another assumption is necessary to solve this problem which is the process should be isothermal.
So
,
,
and ![V_{2}=4.40L](https://tex.z-dn.net/?f=V_%7B2%7D%3D4.40L)
Hence ![P_{2}=\frac{P_{1}V_{1}}{V_{2}}](https://tex.z-dn.net/?f=P_%7B2%7D%3D%5Cfrac%7BP_%7B1%7DV_%7B1%7D%7D%7BV_%7B2%7D%7D)
![\Rightarrow P_{2}=\frac{(163kPa)\times (10.0L)}{4.40L}](https://tex.z-dn.net/?f=%5CRightarrow%20P_%7B2%7D%3D%5Cfrac%7B%28163kPa%29%5Ctimes%20%2810.0L%29%7D%7B4.40L%7D)
![\Rightarrow P_{2}=370.kPa](https://tex.z-dn.net/?f=%5CRightarrow%20P_%7B2%7D%3D370.kPa)
So the final pressure of the gas is 370. kPa
Answer:
Option a. 4 g of He
Explanation:
6.02×10²³ is the Avogadro's number. The amount of units that corresponds to 1 mol, in this case the units are molecules.
Let's find out which mass corresponds to 1 mol (mass / molar mass)
a. 4g / 4g/mol = 1 mol He
b. 14g / 6.94 g/mol = 2.01 mol Li
c. 80g /159.8 g/mol = 0.5 moles Br₂
d. 4g / 2g/mol = 2 mol H₂
Answer:
We need 226 grams of FeS
Explanation:
Step 1: Data given
Mass of FeCl2 = 326 grams
Molar mass FeCl2 = 126.75 g/mol
Step 2: The balanced equation
FeS + 2 HCl → H2S + FeCl2
Step 3: Calculate moles FeCl2
Moles FeCl2 = 326 grams / 126.75 grams
Moles FeCl2 = 2.57 moles
Step 4: Calculate moles FeS needed
For 1 mol H2S and 1 mol FeCl2 produced, we need 1 mol FeS and 2 moles HCl
For 2.57 moles FeCl2 we need 2.57 moles FeS
Step 5: Calculate mass FeS
Mass FeS = 2.57 moles * 87.92 g/mol
Mass FeS = 226 grams FeS
We need 226 grams of FeS