Answer:
a) m_v = m_s ((
)² - 1) , b) m_v = 1.07 10⁻¹⁴ g
Explanation:
a) The angular velocity of a simple harmonic motion is
w² = k / m
where k is the spring constant and m is the mass of the oscillator
let's apply this expression to our case,
silicon only
w₉² = 
k = w₀² m_s
silicon with virus
w² = 
k = w² (m_v + m_s)
in the two expressions the constant k is the same and q as the one property of the silicon bar, let us equal
w₀² m_s = w² (m_v + m_s)
m_v = ()² m_s - m_s
m_v = m_s (()² - 1)
b) let's calculate
m_v = 2.13 10⁻¹⁶ [(
)² - 1)]
m_v = 1.07 10⁻¹⁴ g
Formula of kinetic energy = 0.5*mass*velocity squared so the answer is 11008j
The radar device determines the vehicle's instantaneous speed.
I would argue that the purpose of the device is not to determine
whether individuals are driving safely. They only determine whether
individuals are driving within legal speed limits. There's much more
to 'safe' driving than that, but the radar gun can't detect it.
Complete Question
A truck going 15 km/h has a head-on collision with a small car going 30 km/h. Which statement best describes the situation?
A. the truck has the greater change of momentum because it has the greater mass
B. the car has the greater change of momentum because it has the greater speed
C. neither the car nor the truck changes its momentum in the collision because momentum is conserved
D. they both have the same change in magnitude of momentum because momentum is conserved
E. none of the above is necessarily true
Answer:
D. They both have the same change in magnitude of momentum because momentum is conserved
Explanation:
In order to get a good understanding of the solution above we define some
concetps
Momentum
This is defines quantified motion and can be mathematically represented as
Momentum = Mass of the body × Velocity of the body
According to the Law of conservation of momentum states that when two particles collide together in a system that is being isolated that their total momentum before and after their collision is equal this means that the momentum lost by the truck would be the same as the momentum gained by the small car
