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noname [10]
3 years ago
15

What is the answer to1/2q= -24 ​

Mathematics
2 answers:
Ede4ka [16]3 years ago
7 0
1/2q = -24

1/2q ÷ 1/2 = -24 ÷ 1/2

q = -24 x 2

q = -48

Hope it helps!
Agata [3.3K]3 years ago
3 0

Answer:

48

Step-by-step explanation:

just divide it by 0.5....

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How can i solve 5×23×2
VARVARA [1.3K]

multiply 5 and 2 then that with 23.

5x2=10       23x10=230


3 0
3 years ago
Read 2 more answers
Help meee pleaseeeee
Wittaler [7]

Answer:

1 x 10^21

Step-by-step explanation:

The initial number (2 x 10^4) is in scientific notation.  Scientific notation must be written as: a X 10^n, where 0<a<10 and n is an integer. In this case, the number in scientific notation is being raised to the power of 5.  When we raise a power by another power, we must multiply the power of all the terms by the additional power.  In this case, we would get 2^5 x 10^20, this would be 10 x 10^20.  Since the value of 'a' needs to be greater than 0 and less than 10, we need to move the decimal to the left and add another power to our 10:  1 x 10^21.

7 0
3 years ago
What is the range of the relation (-3,6),(5,2),(-1,-5),(6,-3)
Eddi Din [679]
(-3;\ 6);\ (5;\ 2);\ (-1;-5);\ (6;-3)\\\\the\ domain:\{-3;-1;\ 5;\ 6\}\\\\the\ range:\{-5;-3;\ 2;\ 6\}
6 0
3 years ago
Find the nth term of the sequence 7,25,51,85,127​
olya-2409 [2.1K]

Let <em>a </em>(<em>n</em>) denote the <em>n</em>-th term of the given sequence.

Check the forward differences, and denote the <em>n</em>-th difference by <em>b </em>(<em>n</em>). That is,

<em>b </em>(<em>n</em>) = <em>a </em>(<em>n</em> + 1) - <em>a </em>(<em>n</em>)

These so-called first differences are

<em>b</em> (1) = <em>a</em> (2) - <em>a</em> (1) = 25 - 7 = 18

<em>b</em> (2) = <em>a</em> (3) - <em>a</em> (2) = 51 - 25 = 26

<em>b </em>(3) = <em>a</em> (4) - <em>a</em> (3) = 85 - 51 = 34

<em>b</em> (4) = <em>a </em>(5) - <em>a</em> (4) = 127 - 85 = 42

Now consider this sequence of differences,

18, 26, 34, 42, …

and notice that the difference between consecutive terms in this sequence <em>b</em> is 8:

26 - 18 = 8

34 - 26 = 8

42 - 34 = 8

and so on. This means <em>b</em> is an arithmetic sequence, and in particular follows the rule

<em>b</em> (<em>n</em>) = 18 + 8 (<em>n</em> - 1) = 8<em>n</em> + 10

for <em>n</em> ≥ 1.

So we have

<em>a </em>(<em>n</em> + 1) - <em>a </em>(<em>n</em>) = 8<em>n</em> + 10

or, replacing <em>n</em> + 1 with <em>n</em>,

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 8 (<em>n</em> - 1) + 10

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 8<em>n</em> + 2

We can solve for <em>a</em> (<em>n</em>) by iteratively substituting:

<em>a</em> (<em>n</em>) = [<em>a</em> (<em>n</em> - 2) + 8 (<em>n</em> - 1) + 2] + 8<em>n</em> + 2

<em>a</em> (<em>n</em>) = <em>a </em>(<em>n</em> - 2) + 8 (<em>n</em> + (<em>n</em> - 1)) + 2×2

<em>a</em> (<em>n</em>) = [<em>a</em> (<em>n</em> - 3) + 8 (<em>n</em> - 2) + 2] + 8 (<em>n</em> + (<em>n</em> - 1)) + 2×2

<em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 3) + 8 (<em>n</em> + (<em>n</em> - 1) + (<em>n</em> - 2)) + 3×2

and so on. The pattern should be clear; we end up with

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 8 (<em>n</em> + (<em>n</em> - 1) + … + 3 + 2) + (<em>n</em> - 1)×2

The middle group is the sum,

\displaystyle 8\sum_{k=2}^nk=8\sum_{k=1}^nk-8=\frac{8n(n+1)}2-8=4n^2+4n-8

so that

<em>a</em> (<em>n</em>) = <em>a</em> (1) + (4<em>n</em> ² + 4<em>n</em> - 8) + 2 (<em>n</em> - 1)

<em>a</em> (<em>n</em>) = 4<em>n</em> ² + 6<em>n</em> - 3

4 0
3 years ago
A ball is thrown into the air with an initial upwards velocity of 60ft/s. Its height (h) in feet after t secons is given by the
Strike441 [17]
I believe you will sub. in 3 for t so h=-16(3)^2 + 60(3)+6. then you will just solve!
h=-16(9)+60(3)+6
h= -144 + 180 + 6
h= 42
 so the answer to your question is c. 42 Feet
 Hope this helps! :)

3 0
3 years ago
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