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Natasha2012 [34]
4 years ago
15

What is a hemmoroid?

Chemistry
1 answer:
denpristay [2]4 years ago
8 0
A swollen vein or group of veins in tha region
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ENG
Varvara68 [4.7K]
The sun is my black hole and technically is also the way that urnanus comes in contact with suck m wee wee
8 0
3 years ago
What type of energy does water gain as it sits in the sun?
finlep [7]

Answer:

A. Heat energy

Explanation:

6 0
3 years ago
62 grams of Zn(C2H3O2)4 are dissolved to make a 1.5 M solution. How many milliliters of water are needed?
LenKa [72]
Molarmass of <span>Zn(C2H3O2)4 is 301.5561 g/mol

moles of </span>
<span>Zn(C2H3O2)4
= 62 g * 1 mol/(</span><span>301.5561 g) = 0.2056 mol

concentration = moles / volume
concentration * volume = moles
volume = moles / concentration
volume = 0.2056 mol / 1.5 M
volume = 0.13706 L
volume = 137 mL
volume = 140 mL
</span>


3 0
4 years ago
Read 2 more answers
A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon
ikadub [295]

<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q_1=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_1=675J/^oC\times 29.62^oC=19993.5J

To calculate the heat absorbed by water, we use the equation:

q_2=mc\Delta T

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J

Total heat absorbed = q_1+q_2

Total heat absorbed = [19993.5+114690.12]J=134683.62J=134.7kJ

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol

Hence, the enthalpy of the reaction is 269.4 kJ/mol

6 0
3 years ago
Read 2 more answers
Please help me very easy will biraly and 5 star and thanks
cestrela7 [59]

ITS 40 GRAMS I THINK

7 0
3 years ago
Read 2 more answers
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