Ask question

Ask question

All categories

3 years ago

8

Cole has already taken 7 quizzes during past quarters, and he expects to have 1 quiz during each week of this quarter. Write an

equation that shows the relationship between the number of weeks x and the total number of quizzes y.

1 answer:

san4es73 [151]3 years ago

7 0

Answer:

y = x + 7

Step-by-step explanation:

x = number of weeks

y = the total number of quizzes y.

<em>Cole has already taken 7 quizzes = </em>+ 7

<em>he expects to have 1 quiz during each week of this quarter = </em>1x

y = 1x + 7

y = x + 7

You might be interested in

Please help me 30 points to whoever can do this geometry work sheet please help me I’m so tired

marissa [1.9K]

This is algebra and too blurry to see. for 12 you have
4/3x-1/2x=-5 so 8x-3x/6=-5 and 5x/6=-5 so x=-6

4 0

3 years ago

Misha deposited $3,725 into a savings account 22 years ago. The account has an interest rate of 2.2% and the balance is currentl

Annette [7]

The compounding equation is $A=P(1+ \frac{r}{n}) ^{nt}$ . So

$6012.37 = 3725(1+ \frac{0.022}{n}) ^{22n}$     Divide by 3725

$1.6141= (1+ \frac{0.022}{n}) ^{22n}$

Daily    = $(1+ \frac{0.022}{365}) ^{22*365}$
              = $(1.000060274) ^{8030}$
              = 1.6225
Monthly = $(1+ \frac{0.022}{12}) ^{22*12}$
              = $(1.0018333) ^{264}$
              = 1.6218
Quarter = $(1+ \frac{0.022}{4}) ^{22*4}$
              = $(1.0055) ^{88}$
              = 1.6204
Yearly = $(1+ \frac{0.022}{1}) ^{22*1}$
              = $(1.022) ^{22}$
              = 1.6141

The answer is yearly.

5 0

3 years ago

PLEASEEE HELP MEEEE<br><br>NO LINKSSS

Artemon [7]

Answer:

$\huge\boxed{(2,\ 3);\ (-1,\ 6)}$

Step-by-step explanation:

$f(x)=x^2-2x+3\to y=x^2-2x+3\\f(x)=-x+5\to y=-x+5\\\\\left\{\begin{array}{ccc}y=x^2-2x+3&(1)\\y=-x+5&(2)\end{array}\right$

substitute (1) to (2):

$x^2-2x+3=-x+5$ add x to both sides

$x^2-2x+x+3=-x+x+5$

$x^2-x+3=5$ subtract 5 from both sides

$x^2-x+3-5=5-5$

$x^2-x-2=0\\\\x^2+x-2x-2=0\\\\x(x+1)-2(x+1)=0\\\\(x+1)(x-2)=0\iff x+1=0\ \vee\ x-2=0\\\\\boxed{x=-1\ \vee\ x=2}$

substitute the values of x to (2):

$x=-1\\\\y=-(-1)+5=1+5=6\\\\\huge\boxed{(-1,\ 6)}\\\\x=2\\\\y=-2+5=3\\\\\huge\boxed{(2,\ 3)}$

3 0

2 years ago

Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5

Lesechka [4]

<h3>Answer: E) x^5</h3>

$\sqrt{x^{10}} = x^5$

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is $\sqrt{a^b} = a^{b/2}$

A more general rule is

$\sqrt[n]{a^b} = a^{b/n}$

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

5 0

2 years ago

Read 2 more answers

The perimeter of the triangle

Illusion [34]

Area=228 feet sqa.
Length=12 ft.
Breadth=(228/12) ft.
=19 ft.
Perimeter=2(12+19) ft.
=2×31 ft.
=62 ft.

HOPE IT HELPS UH!!☺️☺️

8 0

2 years ago