The moment of inertia for rolling motion is
I = Mr²
The linear velocity is v = 2 m/s. The rotational velocity is
ω = 2/r
The total KE (kinetic energy) is
KE = (1/2)Mv² + (1/2) I ω²
= (1/2)(M)(4) + (1/2)(Mr²)(4/r²)
= 2M + 2M
= 4M
Answer: 4M
The weight of an object is the strength of the gravitational force on it.
So if the gravitational force changes, the object's weight changes.
Answer:
11.7 m/s
Explanation:
An impulse results in a change of momentum
FΔt = mΔv
Δv = FΔt/m
vf - vi = FΔt/m
vf = vi + FΔt/m
Assuming the original velocity has the positive direction
vf = 40.0 + (-15000)(0.0005)/0.145
vf = -11.7241
|vf| = 11.7 m/s
Answer:
120 deg Unknown = 100 deg Celsius since we know that the ice point is at
0 deg Celsius and the steam point is 100 deg Celsius
So you have 1.2 deg U / 1 deg C
70 deg U / (1.2 deg U / 1 deg c) = 58.3 deg C (temperature in deg Celsius)
Or 58.3deg C * 1.2 deg U / 1 deg C = 70 deg U