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Sliva [168]
3 years ago
13

How many additional electrons does this atom of oxygen need in its valence shell to satisfy the octet rule?

Physics
2 answers:
madam [21]3 years ago
7 0

The answer to the question on Edge is,

A. two

Please vote brainliest (:

Readme [11.4K]3 years ago
5 0

The answer is two..........................................

You might be interested in
Plz help me asap !!!!!!!!!!
nlexa [21]

Answer:

B- 65km

C- 2.8km/h

D- average speed

6 0
3 years ago
What percentage does each parent contribute to a child's genotype?​
bearhunter [10]

Each parent contribute 50 percent. A person have 46 genes and 23 comes from the mother and 23 comes from the father

5 0
3 years ago
Read 2 more answers
A tiger leaps horizontally out of a tree that is 6.00 m high. If he lands 2.00 m from the base of the tree, calculate his initia
Musya8 [376]

Answer:

The initial speed of the tiger is 1.80 m/s

Explanation:

Hi there!

The equation of the position vector of the tiger is the following:

r = (x0 + v0 · t, y0 + 1/2 · g · t²)

Where:

r = position vector at a time t.

x0 = initial horizontal position.

v0 = initial horizontal velocity.

t = time.

y0 = initial vertical position,

g = acceleration due to gravity.

Let´s place the origin of the frame of reference on the ground at the point where the tree is located so that the initial position vector will be:

r0 = (0.00, 6.00) m

We can use the equation of the vertical component of the position vector to obtain the time it takes the tiger to reach the ground.

y = y0 + 1/2 · g · t²

When the tiger reaches the ground, y = 0:

0 = 6.00 m - 1/2 · 9.81 m/s² · t²

2 · (-6.00 m) / -9.81 m/s² = t²

t = 1.11 s

We know that in 1.11 s the tiger travels 2.00 m in the horizontal direction. Then, using the equation of the horizontal component of the position vector we can find the initial speed:

x = x0 + v0 · t

At t = 1.11 s, x = 2.00 m

x0 = 0

2.00 m = v0 · 1.11 s

2.00 m / 1.11 s = v0

v0 = 1.80 m/s

The initial speed of the tiger is 1.80 m/s

4 0
3 years ago
A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th
Rashid [163]

Answer:

The velocity of the particle = -1.92 m/s

The speed of the particle = 5.72 m/s

Explanation:

Given equation of motion;

f(t) = 18 \ + \ \frac{48}{t} \ + \ 1

Velocity is defined as the change in displacement with time.

V = \frac{df(t)}{dt} = -\frac{48}{t^2} \\\\at \ t = 5 \ s\\\\V = -\frac{48}{5^2} = \frac{-48}{25} = - 1.92 \ m/s

The distance traveled by the particle in 5 s:

s = f(5) = 18 + \frac{48}{5} + 1\\\\s= 28.6 \ m

The speed of the particle when t = 5s

Speed = \frac{28.6}{5} = 5.72 \ m/s

6 0
3 years ago
Which do you think changes the land more frozen water or flowing water?
Maksim231197 [3]
I believe flowing water changes the land because eventually frozen water has to melt to flowing water, right?
8 0
3 years ago
Read 2 more answers
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