The relevant equation we can use in this problem is:
h = v0 t + 0.5 g t^2
where h is height, v0 is initial velocity, t is time, g is
gravity
Since it was stated that the rock was drop, so it was free
fall and v0 = 0, therefore:
h = 0 + 0.5 * 9.81 m/s^2 * (4.9 s)^2
<span>h = 117.77 m</span>
Current, I got it right on my quiz
Answer:
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Explanation:
Answer: 2.9kg
let mass be=m ; F=15N; Sin(theta)=32°;g =9.8kgm/s^2.
represent the mass. By resolving forces, we have:
F=mgSin(theta)
15N=mgSin(32°)
m=15N/g×Sin(32°)
m=15N/9.8m/s^2÷Sin(32°)
=2.888kg2.888
≈2.9kg