The equal and opposite force is the force of the stone's gravity pulling up on thy Earth.
<u>Explanation</u>:
- When someone tosses a stone off a cliff, the force of gravity of Earth pulls down and the force of the stone's gravity pulls up on the Earth due to the equal and opposite reaction exerted between the Earth and the stone.
- In Newton's third law, two important features are present. One is the force exerted on two bodies will have the same magnitude but opposite direction. The other feature is force is acting on two different objects.
- This exerted force is equal in magnitude but opposite in direction whereas the gravity exerts a downward force on a stone and upward force on an Earth which is opposite in direction.
Answer:
A measured force of (46.5 0.8 N ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N )
Explanation:
From the question we are told that
Measured force is ![F_M = [46.5 \pm 0.8 \ N ]](https://tex.z-dn.net/?f=F_M%20%20%3D%20%20%5B46.5%20%5Cpm%200.8%20%5C%20%20N%20%5D)
Calculated force is ![F_c = [48.4 \pm 0.6 \ N ]](https://tex.z-dn.net/?f=F_c%20%3D%20%20%5B48.4%20%5Cpm%200.6%20%5C%20%20N%20%5D)
Generally the measured force in interval form is
=> 
Generally the calculated force in interval form is
=> 
Generally looking both interval we see that they do not intersect at any point Hence
A measured force of (46.5 0.8 N ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N )
Answer:
The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
Explanation:
Given;
mass of bullet, m₁ = 4.2 g = 0.0042 kg
mass of hunter + gun = 72.5 kg
velocity of the bullet, u = 965 m/s
Momentum of the bullet when it was fired;
P = mv
P = 0.0042 x 965
P = 4.053 kg.m/s
Determine the recoil velocity of the hunter.
Total momentum = sum of the individual momenta
Total momentum = momentum of the bullet + momentum of the hunter
Apply the principle of conservation of momentum, sum of the momentum is equal to zero.
Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
Answer:
The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Explanation:
Given;
distance between the parallel wires, r = 5.0 cm = 0.05 m
current in the first wire, I₁ = 1.65 A
current in the second wire, I₂ = 3.25 A
The magnitude of the force per unit length between the two wires is calculated as follows;
Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
