Answer
1.5x10^-3 m
24.91x10^5
Explanation:
15 millimeters
- 1 mm = .0015
exponent indicates which way the decimal moved and to how many places
we moved the decimal backwards (negative) 3 spaces
2491 km= 2491000 m
exponent indicates which way the decimal moved and to how many places
we moved the decimal forwards (positive) 5 spaces
2491000.00 --> 24.91000
Answer:
Volume of first solution = 20 Liters
Volume of second solution = 20 Liters
Volume of third solution = 60 Liters
Explanation:
Let the volume second solution used= y
Let the volume of third solution used = 3y
Let the volume of first solution used = 100 - (y +3y)
= 100- 4y
The volume of acid in the first solution ( V₁) = 25% of (100-4y)
= 25-y
The volume of acid in the second solution(V₂) =35% of y
= 0.35y
The volume acid in the third solution (V₃) = 55% of 3y
=1.65y
The Volume of acid in Mixture (V₄) = 45% of 100
= 45
From the conservation of volume:
V₄ = V₁ + V₂ + V₃
45 = (25-y )+ 0.35y + 1.65y
45 =25 -y + 0.35y + 1.65y
45 -25 = y
y = 20
So the volume of first solution used = 100- 4y
= 100- 4(20)
= 20 Liters
So the volume of second solution used = y
= 20 Liters
So the volume of third solution used = 3y
= 3(20)
= 60 Liters
The correct answer is 0.15.
We are aware that there is 0.05 mol of an unidentified hydrocarbon we will refer to as "X" and that its burning produces 6.6 g of carbon dioxide and 3.6 g of water.
These quantities might be converted to moles by applying the following formula:
amount= mass/ relative atomic mass
Thus, the following equation may be written for H2O: moles = 3.6 / 18 = 0.2 and for CO2: moles = 6.6 / 44 = 0.15.
0.05X + x'O2 = 0.15CO2 + 0.2H2O
This may be made simpler by dividing through by 0.05 (this step is likely to be the most helpful to you), resulting in:
1 x + x O2 = 3 co2 + 4 H2O
The hydrocarbon must have been the source of all the carbon in the carbon dioxide and all the hydrogen in the water.
Accordingly, 4 x 2 = 8 moles of H and 3 x 1 = 3 moles of C.
There are 3/1 = 3 Cs and 8/1 = 8 Hs in one X molecule.
This clearly identifies C3H8 or propane as the hydrocarbon X (dividing by 1 seems unnecessary, but it illustrates the process to use if there were more than one mol of X in the first equation).
To learn more about number of moles of carbon dioxide refer the link:
brainly.com/question/12723070
#SPJ9
I would say the answer is... <span>C. AgNO3 + LiOH AgOH + LiNO3
</span>
Good luck!!
Answer:
D. solid candle wax near the flame melts as the candle burns.
