Answer:
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Explanation:
Step 1: Data given
Mass of sodium bicarbonate = 2.7 grams
Step 2: The balanced equation
HCl + NaHCO3 ⇔ NaCl + H2O + CO2
Step 3: Calculate moles NaHCO3
moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles
Step 4: Calculate moles HCl
For 1 mol NaHCO3 we need 1 mol HCl
For 0.032 moles NaHCO3 = 0.032 moles HCl
Step 5: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
mass HCl = 0.032 * 36.46 g/mol= 1.17 grams
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Answer:
Explanation:
%Carbon = mass of carbon / mas of C13H18O2) X100%
= 13X12/ (13X12+18+2X16)X100%
= 156/206) X100%= 75.7%
D = m / V
3.26 = m / 0.313
m = 3.26 x 0.313
m = 1.02038 g
hope this helps!
Answer: A wavelenghth is the<u> distance between successive crests</u> of one <u>wave</u>.
