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kolezko [41]
3 years ago
15

Is the following true or false? If a gas were truly an ideal gas, it would be impossible to liquefy or solidify it by cooling or

by applying pressure.
Chemistry
1 answer:
kirza4 [7]3 years ago
6 0
The answer is true. Gas will always be gas.
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How many protons and electrons are present in Au+?
balandron [24]

Answer:

Protons: 79

Electrons: 78

Explanation:

1. The number of protons is the atomic number (The atomic number for Au on the periodic table is 79)

2. Since the charge is +1 (positive) it means that there's one more proton than electrons. So, 79-1 = 78 electrons

7 0
3 years ago
What is the role of neutrons in an atom??
Colt1911 [192]
They're only found in the nucleus and play an important role in keeping the atom stable because they carry a negative charge to counteract the proton's positive charge. 
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3 years ago
Read 2 more answers
Which is not on a station model? *
Fiesta28 [93]
The answer is fronts
6 0
3 years ago
W = m·g is a form of Newton's ______ Law.<br><br> A)first<br><br> B)second<br><br> C) third
tatuchka [14]

Answer:

B. Second

Explanation:

It is the Law of Motion

3 0
3 years ago
Analysis of Potassium-40 / Argon-40 determines that 37.5% of the Potassium-40 remains and 62.5% has decayed to Argon-40. What is
likoan [24]

Answer:

Option C is correct.

t = 1.95 billion years.

Explanation:

Radioactive decay follows a first order reaction kinetics.

On solving the dynamic equation (the differential equation), this is obtained

C(t) = C₀ e⁻ᵏᵗ

C(t) = amount of radioactive material remaining after time t = 37.5%

C₀ = Initial amount of radioactive material = 100%

t = time that has passed = ?

k = decay constant.

For a first order reaction, the decay constant is related to the half life through the relation

k = (In 2)/T

T = half life = 1.38 billion years

k = (In 2)/1.38

k = 0.5023 per billion years.

C(t) = C₀ e⁻ᵏᵗ

0.375 = e⁻ᵏᵗ

e⁻ᵏᵗ = 0.375

In e⁻ᵏᵗ = In 0.375 = -0.981

-kt = -0.981

t = (0.981/0.5023) = 1.95 billion years.

Hope this Helps!!!

6 0
3 years ago
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