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Igoryamba
3 years ago
7

HELP ASAP 50-50 CHANCE

Chemistry
1 answer:
docker41 [41]3 years ago
4 0

Answer: The answer is A, A new element or different atom formed from the original two.

Hope this helps! :D

-<em>TanqR</em>

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calculate the mass of ammonium sulfate that can be made from 51 grams of ammonia. 2NH₃ + H₂SO₄ → (NH₄)₂SO₄ (keeping the mole con
kap26 [50]

Explanation:

firstly firstly we are to calculate the number of moles of ammonia and using the mole concept of two moles of ammonia gives one mole of ammonium sulphate we can calculate the number of moles of ammonium sulphate and mass

from n=m/mr

3 0
3 years ago
How many molecules of Mg3N2 (magnesium nitride) are formed when excess Mg (magnesium)
dybincka [34]

Explanation:

<em>3Mg(s) + N2(g) = Mg3N2(s)</em>

First check that the equation is balanced. In this case, it is.

Assuming that magnesium is the limiting reactant:

  1. First find the molecular weight using the Periodic Table.

       We find that the atomic mass of magnesium is approximately

       <em>24.3g</em>, so the molecular weight is just <em>24.3g\mol</em>

   

    2. Next we need the mole to mole ratio. As there are <em>3</em>

        magnesiums for <em>1</em> magnesium nitride (shown by the coefficients), the                    

        mole to mole ratio is<em> 1 mol Mg3N2\3 mol Mg.</em>

   

    3. We need the amount of the substance, in grams. Since you have not    

        stated it in the question, I'll just do <em>10g</em> AS AN EXAMPLE. Note that    

       depending on the amount, the LIMITING REAGENT MAY DIFFER.

   4.  Finally, we need the molecular weight of <em>Mg3N2</em>, which we can easily    

        calculate to be around <em>100.9\mol.</em>

<em />

   5.  Putting this all together, we have<em> 10gMg⋅ (mol Mg\24.3gMg) </em>

<em>         (1mol Mg3N2\ 3mol Mg) (100.9g Mg3N2\mol Mg3N2)</em>

     

        the units will cancel to leave <em>gMg3N2</em> (grams of magnesium nitride):

       

<em>        10gMg ⋅ (mol Mg\24.3gMg) (1mol Mg3N2\3mol Mg)</em>

<em>        (100.9g Mg3N2\mol Mg3N2)</em>

<em />

Doing the calculation yields approximately 13.84g.

Assuming that nitrogen is the limiting reactant:

Similarly, following the above steps but with <em>10g</em> of nitrogen yields <em>36.04g</em>

In conclusion, as we produce less amount of <em>Mg3N2</em> when we assumed that <em>Mg</em> was the limiting reagent, magnesium is the limiting reagent and nitrogen is the excess.

Note: This is in THIS CASE, where we have <em>10g</em> of both. The answer may vary depending on the amount of each substance.

7 0
2 years ago
Read 2 more answers
An arrow is fired at a target on a high wall. Which statement correctly describes the change in the energy of the arrow as it mo
grigory [225]

Answer : Option C) The kinetic energy decreases as potential energy increases.

Explanation : As the target is fired high on the wall, the change in the energy that is observed as the arrow moves towards the target is kinetic energy starts to decrease as the arrow reaches nearer towards the target and the potential energy is observed to increase. So, in short the energy transformation is from kinetic energy from a moving arrow to potential energy when the arrow hits the target.

8 0
3 years ago
Read 2 more answers
How much energy is involved to cool 16.2 g of steam at 115.0°C to -2.00°C?
love history [14]

Explanation:

think its specific heat of water = 4.18 J/g°Ci

6 0
3 years ago
When a solution of ammonium chloride, NH4Cl, is added to a solution of lead (II) nitrate , Pb(NO3)2, a white precipitate, PbCl2,
slavikrds [6]

Answer:

B) 2NH_4^+_{(aq)}+2Cl^-_{(aq)}+Pb^{2+}_{(aq)}+2NO_3^-_{(aq)}\rightarrow PbCl_2_{(s)}+2NH^{4+}_{(aq)}+2NO_3^-_{(aq)}

Explanation:

The total ionic equation contains all the species in the reaction in the ionic form.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

Spectator ions are also written in total ionic equations.

The chemical equation is:

2NH_4Cl_{(aq)}+Pb(NO_3)_2_{(aq)}\rightarrow PbCl_2_{(s)}+2NH_4NO_3_{(aq)}

The total ionic equation is -

2NH_4^+_{(aq)}+2Cl^-_{(aq)}+Pb^{2+}_{(aq)}+2NO_3^-_{(aq)}\rightarrow PbCl_2_{(s)}+2NH^{4+}_{(aq)}+2NO_3^-_{(aq)}

5 0
3 years ago
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