What is KUFCA? in science?

Which of these electron transitions correspond to absorption of energy and which to emission?

Monica [59]

The energy will be absorbed for the electron transitions n= 3 to n= 4.

There are two ways in which electrons can transition between energy levels:

Absorption spectra: This type of spectra is seen when an electron jumps from a lower energy level to a higher energy level. In this process, energy is absorbed.
Emission spectra: This type of spectra is seen when an electron jumps from a higher energy level to a lower energy level. In this process, energy is released in the form of photons.

for n=3 to n=4, the equation used to calculate the energy of transition is,

$E = - 2.178$ × $10$ ⁻¹⁸ $J ($ $1 / n$ $i$ ² $- 1/nf$ ² $)$

Thus, for n = 3 to n = 4, as the electron is getting jumped from lower energy level (n = 3) to higher energy level (n = 4), the energy will be absorbed.

For more information about absorption visit the link:

brainly.com/question/14649237?referrer=searchResults

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3 0

2 years ago

For this reaction, 11.5 g nitrogen monoxide reacts with 9.91 g oxygen gas. nitrogen monoxide (g) + oxygen (g) nitrogen dioxide (

Artist 52 [7]

Answer : The mass of nitrogen dioxide is, 17.6 grams

The formula of limiting reagent is, $NO$

The mass of excess reagent remains is, 3.74 grams

Explanation : Given,

Mass of $NO$ = 11.5 g

Mass of $O_2$ = 9.91 g

Molar mass of $NO$ = 30 g/mol

Molar mass of $O_2$ = 32 g/mol

First we have to calculate the moles of $NO$ and $O_2$ .

$\text{Moles of }NO=\frac{\text{Given mass }NO}{\text{Molar mass }NO}$

$\text{Moles of }NO=\frac{11.5g}{30g/mol}=0.383mol$

and,

$\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}$

$\text{Moles of }O_2=\frac{9.91g}{32g/mol}=0.309mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

From the balanced reaction we conclude that

As, 2 mole of $NO$ react with 1 mole of $O_2$

So, 0.383 moles of $NO$ react with $\frac{0.383}{2}=0.192$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $NO$ is a limiting reagent and it limits the formation of product.

Moles of excess reagent remains = 0.309 - 0.192 = 0.117 mol

Now we have to calculate the mass of excess reagent remains.

$\text{ Mass of excess reagent}=\text{ Moles of excess reagent}\times \text{ Molar mass of excess reagent}$

Molar mass of $O_2$ = 32 g/mole

$\text{ Mass of excess reagent}=(0.117moles)\times (32g/mole)=3.74g$

Now we have to calculate the moles of $NO_2$

From the reaction, we conclude that

As, 2 mole of $NO$ react to give 2 mole of $NO_2$

So, 0.383 mole of $NO$ react to give 0.383 mole of $NO_2$

Now we have to calculate the mass of $NO_2$

$\text{ Mass of }NO_2=\text{ Moles of }NO_2\times \text{ Molar mass of }NO_2$

Molar mass of $NO_2$ = 46 g/mole

$\text{ Mass of }NO_2=(0.383moles)\times (46g/mole)=17.6g$

8 0

4 years ago

What type of solid is candle wax? Pls explain

kolbaska11 [484]

<span>the type of solid of the candle wax is amorphous.

as the amorphous is doesn't melt at a certain temperature . and it is amorphous because it gets softer and softer and it doesn't melt at a certain temperature. so the wax shape change and being softer and when it re-cooled its shape will become harder again, without melting at distinct temperature.</span>

5 0

3 years ago

The process by which ice widens and deepends cracks in rock is called

sertanlavr [38]

The process by which ice widens and deepens cracks in rock is called Ice welding.

6 0

3 years ago

Dinitrogen pentoxide decomposes in the gas phase to form nitrogen dioxide and oxygen gas. The reaction is first order in dinitro

vitfil [10]

Answer : The partial pressure of $O_2$ is, 222.93 torr

Explanation :

Half-life = 2.81 hr = 168.6 min