Answer:
See explanation
Explanation:
A balanced chemical reaction equation has the same number of atoms of each element on both sides of the reaction equation.
Hence, for the reaction between KOH and H2SO4, the balanced chemical reaction equation is;
H2SO4(aq) + 2KOH(aq) ---------> K2SO4(aq) + 2H2O(l)
Complete ionic equation;
2H^+(aq) + SO4^2-(aq) + 2K^+(aq) +2OH^-(aq) -------> SO4^2-(aq) + 2K^+(aq) + 2H2O(l)
Net ionic equation;
2H^+(aq) + 2OH^-(aq) -------> 2H2O(l)
Answer:
0, l is n-1 always, ml is l to -l
First, we have to see how K2O behaves when it is dissolved in water:
K2O + H20 = 2 KOH
According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:
c(KOH) : c(K2O) = 1 : 2
So,
c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)
Now we can calculate pH:
pOH= -log c(OH⁻) = -log 0.01 = 2
pH= 14-2 = 12
The correct answer of the given question above would be option D. None of the above. When a solid has a low melting point, it is most likely a simple molecular substance. When it is ionic, covalent or metallic, it is already considered as a solid with a high melting point.
M₁V₁ = M₂V₂
(0.050M)*(10 mL) = (0.10M)*(x)
x = 5 mL
You would take 5 mL of the 0.10 M solution of HCl and add 5 mL of deionized water. Therefore, the total volume will be 10 mL and it will have a molarity of 0.050.
