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nasty-shy [4]
2 years ago
6

Satellites orbit Earth in the .

Chemistry
2 answers:
PilotLPTM [1.2K]2 years ago
6 0

Thermosphere.  In this layer, atoms and molecules escape into space and satellites orbit the earth.

Nana76 [90]2 years ago
3 0

Answer:

Thermosphere: I got it right on my test.

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Name the acids present in Tamarind Tomato and Vinegar?​
OverLord2011 [107]

Answer:

<h3>tartaric acids</h3>

The molecular formula of the citric acid is C6H8O7. The structure of citric acid is as follows: The acid present in tamarind is tartaric acid.

<h3>Vinegar- </h3>

Oxalic

3 0
2 years ago
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The model of a “sea of electrons” helps explain ____.
andriy [413]

Answer:

The correct answer is C.) metallic bonds

Explanation:

Metallic bonds are formed between metal compounds and are very strong. These links are explained by the "sea model of electrons", where valence electrons are ceded by each metal atom, becoming positive ions forming a three-dimensional crystalline network. These electrons move forming a network ("sea") that allows the union of the positive ions formed.

3 0
2 years ago
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For the reaction co(g)+2h2(g)&lt;-&gt;ch3oh(g) at 700. k, equilibrium concentrations are [h2] = 0.072 m, [co] = 0.020 m, and [ch
SVETLANKA909090 [29]
The balanced equation for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃<span>OH(g)

Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as
   k = [</span>CH₃OH(g)] / [CO(g)] [H₂(g) ]²

By substitution,
   k = 0.030 M / 0.020 M x (<span>0.072 M</span>)²
   k = 289.35 M⁻²
6 0
3 years ago
The Law of Conservation of Matter describes how mass is not lost during a chemical reaction.
weeeeeb [17]

False, it states that matter can be nether created nor destroyed

7 0
2 years ago
Read 2 more answers
Sulfur dioxide has a vapor pressure of 462.7 mm Hg at –21.0 °C and a vapor pressure of 140.5 mm Hg at –44.0 °C. What is the enth
stealth61 [152]

Answer : The value of \Delta H_{vap} is 28.97 kJ/mol

Explanation :

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature -21.0^oC = 462.7 mmHg

P_2 = vapor pressure at temperature -44.0^oC = 140.5 mmHg

\Delta H_{vap} = Enthalpy of vaporization = ?

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = -21.0^oC=[-21.0+273]K=252K

T_2 = final temperature = 45^oC=[-41.0+273]K=232K

Putting values in above equation, we get:

\ln(\frac{140.5mmHg}{462.7mmHg})=\frac{\Delta H_{vap}}{8.314J/mol.K}[\frac{1}{252}-\frac{1}{232}]\\\\\Delta H_{vap}=28966.6J/mol=28.97kJ/mol

Therefore, the value of \Delta H_{vap} is 28.97 kJ/mol

4 0
3 years ago
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