So draw a cross! One line segment is KL and the other Mn
4x = (130 - 2x) so x = 65/3
(3y + 40) + (130 -2x) = 180 because the angles are supplementary
plug in x
3y + 40 + 130 - 2(65/3) = 180
so 3y = 95/3
therefore y = 95/6
9514 1404 393
Answer:
- relative maximum: -4
- relative (and absolute) minimum: -5
Step-by-step explanation:
The curve has a relative maximum where values on either side are lower. This looks like a peak in the curve. There is one of those on the y-axis at y = -4.
The relative maximum is -4.
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A relative minimum is a low point, where the curve is higher on either side. There are two of these, located symmetrically about the y-axis. The minimum appears to be about y = -5. (They might be at x = ± 1, but it is hard to tell.)
The relative minima are -5.
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A minimum or maximum is absolute if no part of the curve is lower or higher. Here, the minima are absolute, while the maximum is only relative. (The left and right branches of the curve go higher than y=-4.)
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Identifying the points on the curve should be the easy part. Deciding what the coordinates are can be harder when the graph is like this one.
Answer:
Step-by-step explanation:
As the triangles are similar :
45/55 = (12x - 3)/143
9/11 = (12x - 3)/143
9 x 13 = 12x - 3
12x = 117 + 3
12x = 120
x = 10
