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frosja888 [35]
3 years ago
7

When a train first starts going down the railroad, it is very difficult for it to get going. When it comes to a stop, it has a h

ard time slowing down. Why is this?
A: balanced forces
B: unbalanced forces
C: inertia
Physics
1 answer:
Sindrei [870]3 years ago
8 0
<h2>The option ( c ) is correct</h2>

Explanation:

When we apply the force on any body , the inertia comes into play . It is the tenancy of the the body to oppose the force which tends to change its state .

In first case the train tries to change its state from rest to motion . Thus the inertia of rest opposes this tendency.

In the second case , the train tries to come from motion to the state of rest . Thus again , inertia opposes it .

Therefore inertia is the factor which creates difficulty in both case . Hence option ( c ) is correct  

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True

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If she can throw each rock with a speed of 7.5 m/s relative to the ground, causing the wagon to move, how many rocks must she th
Stels [109]

Complete question:

A child sits in a wagon with a pile of 0.64-kg rocks. If she can throw each rock with a speed of 7.5 m/s relative to the ground, causing the wagon to move, how many rocks must she throw per minute to maintain a constant average speed against a 3.9-N force of friction

Answer:

The number of rocks per minutes thrown is 49 rocks/min

Explanation:

Given;

mass of the rock, m = 0.64 kg

speed of the rock, v = 7.5 m/s

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For an object to move at a constant speed, the applied force must be equal to the frictional force.

f_k = N(F_a)\\\\f_k = N(\frac{mv}{t})\\\\f_k = \frac{N}{t} (mv)\\\\\frac{N}{t} = \frac{f_k}{mv}

where;

F_a is the applied force

N/t is the number of rocks per minutes thrown

Substitute the given parameters;

\frac{N}{t} = \frac{f_k}{mv}\\\\ \frac{N}{t} = \frac{3.9}{0.64*7.5}\\\\ \frac{N}{t} = 0.8125 \ \frac{rocks}{second} * \frac{60 \ seconds}{1 \ min} = 48.75 \ \frac{rocks}{min}  \

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3 years ago
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