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frosja888 [35]
3 years ago
7

When a train first starts going down the railroad, it is very difficult for it to get going. When it comes to a stop, it has a h

ard time slowing down. Why is this?
A: balanced forces
B: unbalanced forces
C: inertia
Physics
1 answer:
Sindrei [870]3 years ago
8 0
<h2>The option ( c ) is correct</h2>

Explanation:

When we apply the force on any body , the inertia comes into play . It is the tenancy of the the body to oppose the force which tends to change its state .

In first case the train tries to change its state from rest to motion . Thus the inertia of rest opposes this tendency.

In the second case , the train tries to come from motion to the state of rest . Thus again , inertia opposes it .

Therefore inertia is the factor which creates difficulty in both case . Hence option ( c ) is correct  

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A thermometer initially reading 212F is placed in a room where the temperature is 70F. After 2 minutes the thermometer reads 125
frez [133]

Answer:

91.3°F

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And m, c, h are all constants from the cooling law relation

From Newton's law of cooling

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- mc (d/dt)(T - T∞) = h (T - T∞)

(d/dt) (T - T∞) = dT/dt (Because T∞ is a constant)

dT/dt = (-h/mc) (T - T∞)

Let (h/mc) be k

dT/(T - T∞) = -kdt

Integrating the left hand side from T₀ to T and the right hand side from 0 to t

In [(T - T∞)/(T₀ - T∞)] = -kt

(T - T∞)/(T₀ - T∞) = e⁻ᵏᵗ

(T - T∞) = (T₀ - T∞)e⁻ᵏᵗ

Inserting the known variables

(T - 70) = (212 - 70)e⁻ᵏᵗ

(T - 70) = 142 e⁻ᵏᵗ

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(T - 70) = 142 e⁻ᵏᵗ

e^(-1.897) = 0.15

T - 70 = 142 × 0.15 = 21.3

T = 91.3°F

7 0
3 years ago
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