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Dmitry_Shevchenko [17]
4 years ago
13

If jupiter were scaled to the size of a basketball, earth would be the closest to the size of

Physics
1 answer:
e-lub [12.9K]4 years ago
7 0
Jupiter's diameter is 11.2 times larger than Earth. This means that Earth would be relatively small. Based on searches around the internet from reliable sources, I can conclude that the earth would be the closest to the size of a marble.
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A lawnmower engine running for 20 min does 4560000 j of work. What is the power output of the engine? (Power: P = W/t)
trasher [3.6K]

Answer:

Power output, P = 3800 watts

Explanation:

It is given that,

Work done by the lawnmover engine, W = 4560000 J

Time taken, t = 20 min = 1200 sec

We have to find the power output of the engine. Power of an engine is given by work done per unit time taken i.e.

P=\dfrac{W}{t}

P=\dfrac{4560000\ J}{1200\ s}

P = 3800 Watts

Hence, the power output of the engine is 3800 watts.

7 0
3 years ago
Please help! Which statements correctly describe the effect of distance in determining the gravitational force and the electrica
Vera_Pavlovna [14]

There are six statements on the list.

The first 2 are true, and the last 2 are true.

The 2 in the middle aren't true.  They are false.

7 0
3 years ago
A particle moves along a straight path through displacement while force acts on it. (Other forces also act on the particle.) Wha
allsm [11]

a) c = 1.85

b) c = 0.8

c) c = 2.33

Explanation:

a)

The displacement of the particle is given by

d=2.2i+cj

While the force applied on the particle is

F=3.2i-3.8 j

So we have a problem in 2-dimensions.

The work done on the particle is given by the scalar product between force and displacement:

W=F\cdot d (1)

Here the work done on the particle is zero, so

W = 0

Therefore from eq(1) we find:

0=(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=7.04\\c=\frac{7.04}{3.8}=1.85

b)

In this problem, the work done on the particle is

W=4.0 J

The force and displacement are still

d=2.2i+cj (displacement)

F=3.2i-3.8 j (force)

Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:

W=F\cdot d

4.0 =(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=3.04\\c=\frac{3.04}{3.8}=0.8

c)

In this problem instead, the work done on the particle is negative:

W=-1.8 J

As before, the force and displacement are

d=2.2i+cj (displacement)

F=3.2i-3.8 j (force)

And so again, we calculate the scalar product between  force and displacement and we equate it to the work done on the particle, -1.8 J.

Doing so, we find:

W=F\cdot d

-1.8=(3.2i-3.8j)\cdot (2.2i+c)=7.04-3.8c\\3.8c=8.84\\c=\frac{8.84}{3.8}=2.33

7 0
3 years ago
What is a hypothesis?
Likurg_2 [28]

Answer:

A

Explanation:

a statement that can be tested through the scientific method

4 0
3 years ago
During a group project, two students constructed a simple machine to add to their Rube Goldberg project. They were told to creat
Zinaida [17]

Answer:

Image B

Explanation:

although I'm not exactly sure, i've recently gotten this question as well. but model B demonstrates the force- distance trade off because you can see how in that image them distance is increased in the force is decreased with the object being shorter. hopefully this helps in some way

4 0
3 years ago
Read 2 more answers
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