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zepelin [54]
2 years ago
10

Three resistors of 100 W, 3900 W, and 1000 W are connected in series across a 200-V battery. What is the voltage drop across the

resistor of value 1000 W?
Physics
1 answer:
Gala2k [10]2 years ago
7 0

Answer:

40 V

Explanation:

 I will assume that  the resistors are

           100 and 3900 and 1000 OHMS    <=====(NOT W)

In series , the resistances add together 100 + 3900 + 1000 = 5000 ohms total

V = IR

I = V / R      so the total current will be   200 v / 5000 ohms = .04 amps

                   this is the current through all of the resistors

      so for the   1000 ohm resistor     V = IR     .04 (1000) = 40 V

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In the formula for water (H20), what does the lack of a subscript after the 0 indicate?
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The lack of a subscript after the 0 means that there is only one oxygen (0).

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The answer to this is B.
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8 0
2 years ago
A 3.0 kg object moving 8.0 m/s in the positive x direction has a one-dimensional elastic collision with an object (mass = M) ini
finlep [7]
<h2>Option 2 is the correct answer.</h2>

Explanation:

Elastic collision means kinetic energy and momentum are conserved.

Let the mass of object be m and M.

Initial velocity object 1 be u₁,  object 2 be u₂

Final velocity object 1 be v₁,  object 2 be v₂

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Final momentum = m x v₁ + M x v₂ = 3 x v₁ + M x 6 = 3v₁ + 6M

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Final kinetic energy = 0.5 m x v₁² + 0.5 M x v₂² = 0.5 x 3 x v₁² + 0.5 x M x 6² = 1.5 v₁² + 18 M

We have

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            24 = 3v₁ + 6M

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             v₁ = 8 - 2M

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            96 = 1.5 v₁² + 18 M

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Substituting  v₁ = 8 - 2M

           (8 - 2M)² + 12 M = 64    

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