Answer:
<h2>4.6 m/s²</h2>
Explanation:
The acceleration of an object given it's velocity and time taken can be found by using the formula
<h3>
![a = \frac{v - u}{t} \\](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7Bv%20-%20u%7D%7Bt%7D%20%20%5C%5C%20)
</h3>
where
v is the final velocity
u is the initial velocity
t is the time taken
a is the acceleration
Since the body is from rest u = 0
From the question we have
![a = \frac{23 - 0}{5} = \frac{23}{5} \\](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7B23%20-%200%7D%7B5%7D%20%20%3D%20%20%5Cfrac%7B23%7D%7B5%7D%20%20%5C%5C%20)
We have the final answer as
<h3>4.6 m/s²</h3>
Hope this helps you
Answer:
if the object is not in motion
Explanation:
Answer:
Minimum DC current
Ampere
Voltage
V
Explanation:
Here in this questions three resistors are used in series
Resistance of cap circuit
![R_1 =\frac{ 8* 2.3}{6} \\R_1 = 3.067](https://tex.z-dn.net/?f=R_1%20%3D%5Cfrac%7B%208%2A%202.3%7D%7B6%7D%20%5C%5CR_1%20%3D%203.067)
Here
is the resistance per cap
Resistance of bus wire
![R_2 = \frac{50 * 4.02 }{1000} \\R_2 = 0.201](https://tex.z-dn.net/?f=R_2%20%3D%20%5Cfrac%7B50%20%2A%204.02%20%7D%7B1000%7D%20%5C%5CR_2%20%3D%200.201)
Where
is the resistance per
feet of bus wire of gauge 16
Resistance of firing line
![R_3 = \frac{(2*1000)* 2.525}{1000} \\R_3 = 5.05](https://tex.z-dn.net/?f=R_3%20%3D%20%5Cfrac%7B%282%2A1000%29%2A%202.525%7D%7B1000%7D%20%5C%5CR_3%20%3D%205.05)
where
is the resistance per
feet of bus wire of gauge 14
Total resistance is equal to
![R = R_1 + R_2 + R_3\\R = 3.067 + 0.201 + 5.05 \\R = 8.318](https://tex.z-dn.net/?f=R%20%3D%20R_1%20%2B%20R_2%20%2B%20R_3%5C%5CR%20%3D%203.067%20%2B%200.201%20%2B%205.05%20%5C%5CR%20%3D%208.318)
Current in firing line is equal to
![1.5 * 6\\= 9](https://tex.z-dn.net/?f=1.5%20%2A%206%5C%5C%3D%209)
Voltage is equal to product of resistance and current
![= 9 * 8.318\\= 74.862](https://tex.z-dn.net/?f=%3D%209%20%2A%208.318%5C%5C%3D%2074.862)
Answer:
12.5N
Explanation:
From newton law of universal gravitation F= GmM/d2.
that means Force is inversely proportional to the square of the distance apart.
F1= 50N, d1=6400km
F2=?, d2=12800km
F1/F2=d2×d2/d1×d1 so we have 50/F2= 12800×12800/6400×6400...F2=6400×6400×50/(12800×12800)=12.5N