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1 year ago

On a planet with different gravity, would the molarity of water be different? explain your reasoning.

1 answer:

5 0

On a planet with different gravity, the molarity of water won't be different as water produces regular natural gravity.

<h3>How to explain the gravity?</h3>

Although sunlight is the energy source, gravity is the main factor driving the water cycle. The Earth's gravity pulls matter downward and toward its center. Gravity is the force that attracts two objects. It pushes water downhill and precipitation from the clouds. Air and ocean water are also moved by gravity.

We understand that even if the gravitational pull varies throughout the universe, the molarity of water would be constant everywhere. This is thus because a substance's mass is unaffected by gravity; only its weight is. The quantity (or mass, indirectly) of a solute is used to calculate the molarity.

Here, on a planet with different gravity, the molarity of water won't be different as water produces regular natural gravity.

Learn more about gravity on:

brainly.com/question/557206

#SPJ1

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Observing neutrinos from the Sun is an important way to check the fusion rate, but it can be very tough to build a machine that

Vika [28.1K]

Answer:

The trouble that the most recent experiment, Borexino, have to overcome was that

neutrinos hardly interact with matter and so radioactive decay of ant material inside the detector could look exactly like a neutrino interaction too

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3 years ago

If you apply an unbalanced force to this object it will ______. Mention all that will apply: change velocity, accelerate, change

Papessa [141]

Answer:

All of them: change velocity, accelerate, change position

Explanation:

We can answer this question by using Newton's second law:

F = ma

where

F is the net force on the object

m is the mass of the object

a is the acceleration

We notice that when there is an unbalanced force on the object, $F\neq 0$ , and therefore

$a\neq 0$

whcih means that the object will accelerate.

But acceleration is the rate of change of velocity, v:

$a=\frac{\Delta v}{\Delta t}$

And so,

$\Delta v \neq 0$

which means that the object will change velocity.

If the object is changing velocity, this means that it is also moving: therefore, the position of the object must be changing, so also the option "change position" is correct.

6 0

3 years ago

Carry out the following arithmetic operations. (Enter your answers to the correct number of significant figures.) My Notes Ask Y

morpeh [17]

Answer :

(a) The answer will be $\Rightarrow 562$

(b) The answer will be $\Rightarrow 2.0$

(c) The answer will be $\Rightarrow 49.32$

Explanation :

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

(a) The sum of the measured values 521, 31.4, 0.85, and 9.0

$521+31.4+0.85+9.0$

$\Rightarrow 562.25$

In the given expression, 521 has 3 significant figures, 31.4 has 3 significant figures, 0.85 has 2 significant figures and 9.0 has 2 significant figures. From this we conclude that least precise number present after the decimal point is 0.

Thus, the answer will be $\Rightarrow 562$

(b) The product 0.0052 × 386.2

$(0.0052)\times (386.2)$

$\Rightarrow 2.00824$

In the given expression, 0.0052 has 2 significant figures and 386.2 has 4 significant figures. From this we conclude that 2 is the least significant figures in this problem. So, the answer should be in 2 significant figures.

Thus, the answer will be $\Rightarrow 2.0$

(c) The product $15.70\times \pi$

The value of $\pi$ = 3.141414 = $3.\bar {14}$

$\pi$ is an irrational number.

$(15.70)\times (3.1414)$

$\Rightarrow 49.31998$

In the given expression, 15.70 has 4 significant figures and $3.\bar {14}$ has infinite significant figures. From this we conclude that 4 is the least significant figures in this problem. So, the answer should be in 4 significant figures.

Thus, the answer will be $\Rightarrow 49.32$

3 0

4 years ago

Acceleration causes a shift of weight to the ______.

marta [7]

Vehicle weight shifts can be backward forward. In this particular case accelerating to fast would cause a shift of weight backwards. Breaking too quickly on the other hand would cause weight to shift forward. You have seen this while in a car or a bus at the traffic light. As the vehicle breaks you are pulled forward as it starts moving you are pulled backwards.

7 0

3 years ago

Four main types of resistant forces

kondaur [170]

Applied Force, Gravity Force, Normal Force, Friction Force, Air Resistance Force, Tension Force, Spring Force. I know this is more than four but I hope this helps :)

3 0

3 years ago