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stellarik [79]
3 years ago
9

WILL GIVE BRAINLIEST

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

C. 846 in.^2

Step-by-step explanation:

Look at the net.

There is one rectangle that is (21 + 3 + 21 + 3) inches long. Its length is 48 inches long. Its width is 15 inches.

There there are two small rectangles. Both are 3 inches wide and 21 inches long. The total length is (21 + 21) inches = 42 inches

total area = 48 in. * 15 in. + 42 in. * 3 in.

total area = 720 in.^2 + 126 in. * 3 in.

total area = 846 in.^2

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lubasha [3.4K]
-6 is the answer since 6*-1 is -6
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3 years ago
Jamie is selling tickets at a whale watch at a local beach.The tickets cost $24.40 for an adult and $14.50 for a child.Jamie ear
wariber [46]
30% = .3

.3(24.40a + 14.50c)

24.40 = cost of adult ticket
14.50 = cost of child ticket
a = # of adult tickets sold
c = # of child tickets sold

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answer: 7.32a + 4.35c 

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3 years ago
Denise, Keith and Tim live in the same neighborhood. Denise lives 0.3 mile from Keith. The distance that Tim and keith live from
makvit [3.9K]
0.3 * 0.2 = 0.06 miles. :)
7 0
4 years ago
Read 2 more answers
Susan drove at an average speed of 30 miles per hour for the first 30 miles of a trip and then at an average speed of 60 miles p
maxonik [38]

Answer: option B is the correct answer.

Step-by-step explanation:

Susan drove at an average speed of 30 miles per hour for the first 30 miles of a trip.

Time = distance/speed

This means that time spent by Susan in travelling the first 30 miles would be

Time = 30/30 = 1 hour

He travelled at an average speed of 60 miles per hour for the remaining 30 miles of the trip.

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7 0
3 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

8 0
3 years ago
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