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stellarik [79]
3 years ago
9

WILL GIVE BRAINLIEST

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

C. 846 in.^2

Step-by-step explanation:

Look at the net.

There is one rectangle that is (21 + 3 + 21 + 3) inches long. Its length is 48 inches long. Its width is 15 inches.

There there are two small rectangles. Both are 3 inches wide and 21 inches long. The total length is (21 + 21) inches = 42 inches

total area = 48 in. * 15 in. + 42 in. * 3 in.

total area = 720 in.^2 + 126 in. * 3 in.

total area = 846 in.^2

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marishachu [46]
1. You have that:

 - The homeowner<span> want the length of the swimming pool to be 4 feet longer than its width.</span> 
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 2. Therefore, the tota area is:

 At=L2xW2

 L2 is the lenght of the walkway (L2=L1+3+3⇒L2=(W1+4+6)⇒L2=W1+10).
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 L1=W1+4
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