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Whitepunk [10]
3 years ago
10

A hot air balloon has a volume of 2,510,000L at a pressure of 105 kPa and 122 degrees Celcius. If the balloon increased to 2,600

,000L and the temperature increased to 150 degrees Celcius, what would be the pressure of the balloon?
Chemistry
1 answer:
valina [46]3 years ago
7 0

Answer: The new pressure of the balloon is 108 kPa

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 105 kPa

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2510000 L

V_2 = final volume of gas = 2600000 L

T_1 = initial temperature of gas = 122^0C=(122+273)K=395K

T_2 = final temperature of gas = 150^0C=(150+273)K=423K

Now put all the given values in the above equation, we get:

\frac{105\times 2510000}{395}=\frac{P_2\times 2600000}{423}

P_2=108kPa

The new pressure of the balloon is 108 kPa

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Because when the cells divide (resulting in more cells) the multicellular organism mantains its strong cells and when one cell is damaged the other cells compensate for that damaged cell.
4 0
3 years ago
How would a collapsing universe affect light emitted from clusters and superclusters? A. Light would acquire a blueshift. B. Lig
Lady_Fox [76]

Answer:

Choice A: Light would acquire a blueshift.

Explanation:

When a universe collapses, clusters of stars start to move towards each other. There are two ways to explain why light from these stars will acquire a blueshift.

Stars move toward each other; Frequency increases due to Doppler's Effect.

The time period t of a beam of light is the same as the time between two consecutive peaks. If \lambda is the wavelength of the beam, and both the source and observer are static, the time period T will be the same as the time it takes for light travel the distance of one \lambda (at the speed of light in vacuum, c).

\displaystyle t = \frac{\lambda}{c}.

Frequency f is the reciprocal of time period. Therefore

\displaystyle f = \frac{1}{t} = \frac{c}{\lambda}.

Light travels in vacuum at a constant speed. However, in a collapsing universe, the star that emit the light keeps moving towards the observer. Let the distance between the star and the observer be d when the star sent the first peak.

  • Distance from the star when the first peak is sent: d.
  • Time taken for the first peak to arrive: \displaystyle t_1 =\frac{d}{c}.

The star will emit its second peak after a time of. Meanwhile, the distance between the star and the observer keeps decreasing. Let v be the speed at which the star approaches the observer. The star will travel a distance of v\cdot t before sending the second peak.

  • Distance from the star when the second peak is sent: d - v\cdot t.
  • Time taken for the second peak to arrive: \displaystyle t_2 =t + \frac{d - v\cdot t}{c}.

The period of the light is t when emitted from the star. However, the period will appear to be shorter than t for the observer. The time period will appear to be:

\begin{aligned}\displaystyle t' &= t_2 - t_1\\ &= t + \frac{d - v\cdot t}{c} - \frac{d}{c}\\&= t + (\frac{d}{c} - \frac{v\cdot t}{c}) -\frac{d}{c}\\&= t - \frac{v\cdot t}{c} \end{aligned}.

The apparent time period t' is smaller than the initial time period, t. Again, the frequency of a beam of light is inversely proportional to its period. A smaller time period means a higher frequency. Colors at the high-frequency end of the visible spectrum are blue and violet. The color of the beam of light will shift towards the blue end of the spectrum when observed than when emitted. In other words, a collapsing universe will cause a blueshift on light from distant stars.

The Space Fabric Shrinks; Wavelength decreases as the space is compressed.

When the universe collapses, one possibility is that clusters of stars move towards each other. Alternatively, the space fabric might shrink, which will also bring the clusters toward each other.

It takes time for light from a distant cluster to reach an observer on the ground. The space fabric keeps shrinking while the beam of light makes its way through the space. The wavelength of the beam will shrink at the same rate. The wavelength of the beam of light will be shorter by the time the beam arrives at its destination.

Colors at the short-wavelength end of the visible spectrum are blue and violet. Again, the color of the light will shift towards the blue end of the spectrum. The conclusion will be the same: a collapsing universe will cause a blueshift on light from distant stars.

8 0
3 years ago
When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find
ryzh [129]
The balanced equation is 
4Fe+3O₂⇒2Fe₂O₃

We know that the mole of Fe₂O₃ is 6, and since the ratio between oxygen and <span>Fe₂O₃ is 3:2, we can see that

3:2 = x:6 (3 oxygen moles can make 2 </span>Fe₂O₃ moles = x oxygen moles can make 6 <span>Fe₂O₃ moles)
</span><span>
Multiply outside and inside (3*6 , 2*x) and put them on opposing sides of the equation

2*x = 3*6
2x=18
x=9
Therefore 9 moles of oxygen is needed.

</span>
6 0
3 years ago
Read 2 more answers
which solution below would be considered the most acidic?a. 2.9 x 10-4 m hclb. 4.5 x 10-5 m hno3c. 1.0 x 10-7 m nacld. 1.5 x 10-
kkurt [141]

Answer:

a. 2,9x10⁻⁴ M HCl

Explanation:

A solution is considered acidic when its concentration of H⁺ is higher than 1x10⁻⁷. The higher concentration of H⁺ will be the most acidic solution.

a. 2,9x10⁻⁴ M HCl. In water, this solution dissolves as H⁺ and Cl⁻. That means concentration of H⁺ is 2,9x10⁻⁴ M.

b. 4,5x10⁻⁵M HNO₃. In the same way, concentration of H⁺ is 4,5x10⁻⁵M.

c. 1,0x10⁻⁷M NaCl. As this solution doesn't produce H⁺, the solution is not acidic

d. 1,5x10⁻²M KOH. This solution produce OH⁻. That means the solution is basic nor acidic.

Thus, the solution considered the most acidic is a. 2,9x10⁻⁴ M HCl, because has the higher concentration of H⁺.

I hope it helps!

7 0
3 years ago
Benzene can be nitrated with a mixture of nitric and sulfuric acids. How do we do that?
Montano1993 [528]

Answer:

We can do the nitration of benzene by treating the benzene with a mixture of nitric acid and sulphuric acid by not extending the temperature of 50°C

Explanation:

Nitration of benzene takes place by treating the benzene with a mixture of nitric acid and sulphuric acid at low temperatures such as the temperatures below 50°C

The nitration of benzene takes place through electrophilic substitution reaction

In this reaction the electrophile is nitronium ion (NO2+) which performs an electrophilic substitution reaction on the benzene ring and during the reaction an intermediate will also be formed in which there will be positive charge distributed in the benzene

These electrophile is generated when nitric acid is treated with sulphuric acid

As nitric acid is a strong oxidising agent, here in this case the oxidation state of nitrogen will change from +5 to +3

The reactions regarding the nitration of benzene is present in the file attached

5 0
3 years ago
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