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3 years ago

Motion is

Physics

1 answer:

Sladkaya [172]3 years ago

7 0

Answer:

a change of position in relation to another object.

Explanation:

Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.

Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, displacement, position, etc.

Hence, motion is a change of position in relation to another object.

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A stone is launched at an angle of 50 degree with initial velocity of 22m/s. Find out its initial and final velocity.

ss7ja [257]

(a) The initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.

(b) The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.

<h3>Initial vertical velocity</h3>

The initial vertical velocity of the stone is calculated as follows;

Vi = Vsinθ

Vi = 22 x sin(50)

Vi = 16.85 m/s

<h3>Initial horizontal velocity</h3>

Vxi = V cosθ

Vxi = 22 x cos(50)

Vxi = 14.14 m/s

<h3>Final vertical velocity of the stone</h3>

Vf = Vi - gt

where;

Vf is the final vertical velocity = 0 at maximum height

<h3 /><h3>Final horizontal velocity of the stone</h3>

Vfx = Vxi = 14.14 m/s

Thus, the initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.

The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.

Learn more about vertical velocity here: brainly.com/question/24949996

#SPJ1

3 0

2 years ago

A mole of gas at 0.0oC and 760. torr occupies 22.4 L. What is the volume of this gas at 25.oC and 760. torr

daser333 [38]

Answer:

Explanation:

Given

Temperature of gas at First stage $T_1=0^{\circ}C\approx 273\ K$

Pressure of gas at First stage $P_1=760\ torr$

Volume Occupies $V_1=22.4\ L$

If the Pressure and Temperature at second stage is

$P_2=760\ torr$

$T_2=25^{\circ}C\approx 298\ K$

Using ideal gas Equation

$PV=nRT$

where P=Pressure

V=volume

R=Universal Gas constant

T=Temperature

n=no of moles

as n and R is constant therefore

$\frac{PV}{T}=constant$

thus $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$V_2=\frac{760}{760}\times \frac{298}{273}\times 22.4$

$V_2=24.45\ L$

8 0

3 years ago

A high school physics instructor catches one of his students chewing gum in class. He decides to discipline the student by askin

kap26 [50]

Answer:

a) $\omega \approx 219.911\,\frac{rad}{s}$ , b) $\alpha = 16.916\,\frac{rad}{s^{2}}$ , c) $a_{t} = 1.776\,\frac{m}{s^{2}}$ , d) $a_{n} = 5077.889\,\frac{m}{s^{2}}$ , e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation, f) Zero, g) $v = 23.091\,\frac{m}{s}$ .

Explanation:

a) The maximum angular velocity of the fan is:

$\omega = (35\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )$

$\omega \approx 219.911\,\frac{rad}{s}$

b) The angular acceleration of the fan is:

$\alpha = \frac{\omega-\omega_{o}}{t}$

$\alpha = \frac{219.911\,\frac{rad}{s}-0\,\frac{rad}{s}}{13\,s}$

$\alpha = 16.916\,\frac{rad}{s^{2}}$

c) The magnitude of the tangential aceleration is:

$a_{t} = (16.916\,\frac{rad}{s^{2}} )\cdot (0.105\,m)$

$a_{t} = 1.776\,\frac{m}{s^{2}}$

d) The magnitude of the centripetal acceleration is:

$a_{n} = (219.911\,\frac{rad}{s} )^{2}\cdot (0.105\,m)$

$a_{n} = 5077.889\,\frac{m}{s^{2}}$

e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation.

f) When fan is at full speed, it rotates at constant rate and, hence, there is no angular acceleration. Besides, the tangential acceleration experimented by the gum is zero.

g) The linear speed of the gum is:

$v = (219.911\,\frac{rad}{s} )\cdot (0.105\,m)$

$v = 23.091\,\frac{m}{s}$

5 0

3 years ago

Which sentence best describes a role of gravity in the formation of the

enyata [817]

Answer:

I think it's option D

Explanation:

I think it's option D but not so sure

8 0

3 years ago

The heat flux for a given wall is in the x-direction and given as q^n = 11 W/m^2, the walls thermal conductivity is 1.7 W/mK and

MrMuchimi

Answer:

$\frac{dT}{dx} = 6.47 ^oC/m$

Also as we can see the equation that heat flux directly depends on the temperature gradient so more is the temperature gradient then more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the heat will flow inwards

Explanation:

As we know that heat flux is given by the formula

$q^n = K\frac{dT}{dx}$

here we know that

K = thermal conductivity

$\frac{dT}{dx}$ = temperature gradient

now we know that

$q^n = 11 W/m^2$

also we know that

K = 1.7 W/mK

now we have

$11 = 1.7 \frac{dT}{dx}$

so temperature gradient is given as

$\frac{dT}{dx} = \frac{11}{1.7} = 6.47 K/m$

also in other unit it will be same

$\frac{dT}{dx} = 6.47 ^oC/m$

Also as we can see the equation that heat flux directly depends on the temperature gradient so more is the temperature gradient then more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the heat will flow inwards

5 0

3 years ago