Answer:
a)10.08 m/s
b)3.36 m/s
Explanation:
Given that
distance s₁= 160 m
time t₁= 17 s
distance s₂= 80 m
time t₂ = 6.8 s
As we know that
Total distance = Total time x Average speed
s₁ + s₂ = (t₁ + t₂ ) Vavg
Vavg=10.08 m/s
Total displacement = Total time x Average velocity
s₁ - s₂ = (t₁ + t₂ ) Vavg
Vavg=3.36 m/s
a)10.08 m/s
b)3.36 m/s
The equatorial radius of the earth is
r = 6378 km = 6378 x 10³ m
The earth makes 1 revolution in 24 hours.
The angular velocity is
ω = (2π rad)/(24*3600 s) = 7.2722 x 10⁻⁵ rad/s
The tangential velocity (linear velocity) at a point on the equator is
v = rω
= (6378 x 10³ m)*(7.2722 x 10⁻⁵ rad/s)
= 463.8 m/s
Answer: 463.8 m/s
Answer:
V = I × R and the power law equation (formula): P = I × V. P = power