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dybincka [34]
3 years ago
13

Effect of impurities and temperature to surface tension​

Physics
1 answer:
oksano4ka [1.4K]3 years ago
8 0
In general, surface tension decreases when temperature increases because cohesive forces decrease with an increase of molecular thermal activity. The influence of the surrounding environment is due to the adhesive action of liquid molecules that they have at the interface.
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When a person wearing a helmet rides a bicycle, the helmet experiences which type of friction?
vodomira [7]

Answer:

B

Explanation:

3 0
3 years ago
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A 2200-kg railway freight car coasts at 4.1 m/s underneath a grain terminal, which dumps grain directly down into the freight ca
777dan777 [17]

Answer:

The answer is "2.41 \times 10^3"

Explanation:

Given:  

m_i = 2000 \ kg \\\\v_i= 4.1 \ \frac{m}{s} \\\\v_f = 3.4 \ \frac{m}{s} \\

Using formula:  

\to m_iv_i = m_fv_f \\\\\to m_f= \frac{m_iv_i}{v_f}

p_i, p_f = system initial and final linear momentum.

V_i, v_f = system original and final linear pace.

m_i = original weight of the car freight.

m_f= car's maximum weight

= \frac{ 2000 \times 4.1}{3.4}\\\\= \frac{ 8.2\times 10^3}{3.4}\\\\= 2.41 \times 10^3

\boxed{m_f = 2.41 \times 10^3}

8 0
3 years ago
If a spring is stretched 4m from its starting length when 20n of force is applied, then how much work (in joules) is done by the
lys-0071 [83]

ANSWER:

250 J

STEP-BY-STEP EXPLANATION:

F = 20N is required to stretch the spring by 4 meters

We know that the force is equal to:

F=k\cdot x

We solve for k (spring constant):

k=\frac{F}{x}=\frac{20}{4}=5\text{ N/m}

The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:

\begin{gathered} W=\frac{1}{2}k\cdot x^2 \\ \text{ Replacing} \\ W=\frac{1}{2}\cdot5\cdot10^2 \\ W=250\text{ J} \end{gathered}

The work required is 250 joules.

5 0
1 year ago
Considering the symmetry of the charge distribution, determine the symmetry of the electric field and choose one of the followin
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Answer:

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Explanation:

4 0
3 years ago
A light beam is traveling through an unknown substance. When it exits that substance and enters into air, the angle of reflectio
bogdanovich [222]

Answer:

0.79

Explanation:

Using Snell's law, we have that:

n(1) * sin θ1 = n(2) * sinθ2

Where n(1) = refractive index of air = 1.0003

θ1 = angle of incidence

n(2) = refractive index of second substance

θ2 = angle of refraction

The angle of reflection through the unknown substance is the same as the angle of incidence of air. This means that θ1 = 32°

=> 1.0003 * sin32 = n(2) * sin42

n(2) = (1.0003 * sin32) / sin42

n(2) = 0.79

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3 years ago
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