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3 years ago

Effect of impurities and temperature to surface tension

1 answer:

8 0

In general, surface tension decreases when temperature increases because cohesive forces decrease with an increase of molecular thermal activity. The influence of the surrounding environment is due to the adhesive action of liquid molecules that they have at the interface.

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Near the surface of Venus, its atmosphere has a pressure fv= 91 times the pressure of Earth's atmosphere, and a particle density

yaroslaw [1]

Answer:

Explanation:

We shall use gas law equation and modify it to include number density of particle as follows

PV = n RT , n is no of moles

P = (n / V) RT

At earth , P = a atm , n = 6.02 x 10²⁶/22.4 , V = 1 m³ , R is constant , T = 273

(1 mole of a gas occupies 22.4 litre volume and contains 6.02 x 10²³ no of gas molecules . 1 liter = 10⁻³ m³ . )

1 = 6.02 x 10²⁶ x R x 273 / 22.4

At Venus P = 91 atom , n = 1.05 x 10²⁷ , V = 1 m³ , R is constant , T = ?

91 = 1.05 x 10²⁷ R x T

dividing the two equations

91 / 22.4 = 1.05 x 10²⁷ R x T / 6.02 x 10²⁶ x R x 273

91 x 6.02 x 273/ 22.4 = 1.05 x 10 T

T = 91 x 6.02 x 273 / (10.5 x 22.4 )

= 635.86 K

= 362.86 degree Celsius.

6 0

3 years ago

7. Una locomotora de 80.000 kilogramos de masa, parte del reposo y a los 10 segundos lleva una velocidad de 36Km/h. Halla: A. La

Tasya [4]

Answer:

a) La aceleración del movimiento es 1 metros por segundo al cuadrado, b) La fuerza que causa el movimiento es 80.000 newtons.

Explanation:

a) Supóngase que la locomotora acelera uniformemente, la aceleración se está descrita por la siguiente ecuación cinemática:

$v = v_{o}+a\cdot t$

Donde:

$v_{o}$ - Rapidez inicial, medida en metros por segundo.

$v$ - Rapidez final, medida en metros por segundo.

$a$ - Aceleración, medida en metros por segundo al cuadrado.

$t$ - Tiempo, medido en segundos.

Se despeja la aceleración:

$a = \frac{v-v_{o}}{t}$

Si $v_{o} = 0\,\frac{m}{s}$ , $v = 10\,\frac{m}{s}$ y $t = 10\,s$ , la aceleración del movimiento es:

$a = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{10\,s}$

$a = 1\,\frac{m}{s^{2}}$

La aceleración del movimiento es 1 metros por segundo al cuadrado.

b) Dado que una locomotora es un sistema de masa constante, la fuerza ( $F$ ) que genera el movimiento es igual a:

$F = m\cdot a$

Donde:

$m$ - Masa, medida en kilogramos.

$a$ - Aceleración, medida en metros por segundo al cuadrado.

Dados que $m = 80.000\,kg$ y $a = 1\,\frac{m}{s^{2}}$ , la fuerza que causa el movimiento es:

$F = (80.000\,kg)\cdot \left(1\,\frac{m}{s^{2}} \right)$

$F = 80.000\,N$

La fuerza que causa el movimiento es 80.000 newtons.

8 0

3 years ago

A ball with a mass of 3 kg moving at 5 m/s collides with a 9 kg ball at rest. After the collision, the impacting (3 kg) ball bou

Andru [333]

Answer:

The second ball moves with 0.83 m/s forward.

Explanation:

Given;

mass of the first ball, m₁ = 3 kg

initial velocity of the first ball, u₁ = 5 m/s

final velocity of the first ball, v₁ = 2.5 m/s

mass of the second ball, m₂ = 9kg

initial velocity of the second ball, u₂ = 0

final velocity of the second ball, v₂ = ?

From the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(3x5) + (9x0) = (3x2.5) + (9v₂)

15 = 7.5 + 9v₂

15 - 7.5 = 9v₂

9v₂ = 7.5

v₂ = 7.5/9

v₂ = 0.83 m/s

The second ball moves with 0.83 m/s forward.

6 0

4 years ago

Four rods that obey Hooke's law are each put under tension. (a) A rod 50.0 cm50.0 cm long with cross-sectional area 1.00 mm21.00

deff fn [24]

Answer:

c < a = b

Explanation:

The tensile stress = Force applied/(Cross sectional area)

(a) The applied force = 200 N

The cross sectional area = 1.00 mm² = 1 × 10⁻⁶ m²

The tensile stress = 200 N/(1 × 10⁻⁶ m²) = 200,000,000 Pa = 200 MPa

(b) The applied force = 200 N

The cross sectional area = 1.00 mm² = 1 × 10⁻⁶ m²

The tensile stress = 200 N/(1 × 10⁻⁶ m²) = 200,000,000 Pa = 200 MPa

The cross sectional area = 2.00 mm² = 2 × 10⁻⁶ m²

The tensile stress = 100 N/(2 × 10⁻⁶ m²) = 50,000,000 Pa = 50 MPa

Therefore, the tensile stress from smallest to largest are;

(a) 50 MPa, < (b) 200 MPa = (a) 200 MPa

Therefore, we have;

c < a = b.

8 0

3 years ago

astone is thrown upwards with an initial velocity of 25m/s at ange of 30 to the ground. work out the stones horizantal range?

Vadim26 [7]

Explanation:

$R = \dfrac{v_0^2}{g}\sin{2\theta} = \dfrac{(25\:\text{m/s})^2}{9.8\:\text{m/s}^2}\sin{60°}$

$\:\:\:\:=55.2\:\text{m}$

4 0

3 years ago

Effect of impurities and temperature to surface tension​

Effect of impurities and temperature to surface tension