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Ahat [919]
3 years ago
14

You found the distance that you will cover while braking. You can use the expected amount of time for braking to check your answ

er for distance.
Using the information given in the introduction and the value for distance that you found above, determine the time required for you to stop once you press the brakes. Note that the time for braking is just the time interval t3-t2.
This is the information given in the introduction:_______.
You are driving down the highway late one night at 20 m/swhen a deer steps onto the road 35m in front of you. Your reaction time before stepping on the brakes is 0.50s, and the maximum deceleration of your car is 10m/s2. How much distance is between you and the deer when you come to a stop?
Physics
1 answer:
katrin [286]3 years ago
3 0

Answer:

Explanation:

First we need to determine the distance covered during deceleration. According to the equation of motion.

S = ut+1/2at²

Given:

u = 20m/s

t = 0.50s

a = -10m/s (deceleration is negative acceleration)

S = 20²+1/2(-10)(0.5)²

S = 400-5(0.5)²

S = 400-5(0.25)

S = 400-1.25

S = 398.75m

If the deer steps onto the road 35m in front of you, the distance between you and the deer when you come to a stop will be 398.75-35 = 363.75m

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PLEASE HELP PLEASEE. Suppose the mass of a car is 1200 kg and the mass of the driver is 65 kg what is the total combined mass of
Vika [28.1K]

Answer:

If the mass of a car is 1200 kg, and the mass of the driver is 65 kg, the total combined mass of the car and driver expressed with the correct number of significant figures is 1265 kg.

4 0
3 years ago
A uniform beam resting on two pivots has a length L = 6.00 m and weight M = 220 lbs. The pivot under the left end exerts a norma
gulaghasi [49]

Answer:

x = 4,138 m

Explanation:

For this exercise, let's use the rotational equilibrium equation.

Let's fix our frame of reference on the left side of the pivot, the positive direction for anti-clockwise rotation

         ∑ τ = 0

         n₁ 0 - W L / 2 + n₂ 4 - W_woman  x = 0

         x = (- W L / 2 + 4n2) / W_woman

Let's reduce the magnitudes to the SI System

         M = 6 lbs (1 kg / 2.2 lb) = 2.72 kg

         M_woman = 130 lbs = 59.09 kg

Let's write the transnational equilibrium equation

         n₁ + n₂ - W - W_woman = 0

         n₁ + n₂ = W + W_woman

        n₁ + n₂ = (2.72 + 59.09) 9.8

At the point where the system begins to rotate, pivot 1 has no force on it, so its relation must be zero (n₁ = 0)

          n₂ = 605,738 N

 

Let's calculate

         x = (-2.72 9.8 6/2 + 4 605.738) / 59.09 9.8

         x = 4,138 m

4 0
4 years ago
A 15 kg box sits still on a rough inclined plane (no math required here).
nexus9112 [7]

Answer:

Explanation:

The force of friction equals the sine component of the force due to gravity

3 0
3 years ago
Which element of variation would not be affected by adding the data value 15 to the data set {3, 5, 6, 8, 9, 10, 13, 14}?
Anna11 [10]
The answer to this would be 15
4 0
3 years ago
A 250. mL sample of gas at 1.00 atm and 20.0°C has the temperature increased to 40.0°C and the volume increased to 500. mL. What
ladessa [460]

Answer:

New pressure is 0.534 atm

Explanation:

Given:

Initial volume of the gas, V₁ = 250 mL

Initial pressure of the gas, P₁ = 1.00 atm

Initial temperature of the gas, T₁ = 20° C = 293 K

Final volume of the gas, V₂ = 500 mL

Final pressure of the gas = P₂

Final temperature of the gas, T₁ = 40° C = 313 K

now,

we know for a gas

PV = nRT

where,

n is the moles

R is the ideal gas constant

also, for a constant gas

we have

(P₁V₁/T₁) = (P₂V₂/T₂)

on substituting the values in the above equation, we get

(1.00 × 250)/293 = (P₂ × 500)/313

or

P₂ = 0.534 atm

Hence, the <u>new pressure is 0.534 atm</u>

5 0
3 years ago
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