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galina1969 [7]
3 years ago
15

a) When we were examining the Electromagnetic Tab, we saw that a flow of electrons or a current as we say it, creates a magnetic

field. What about the converse, can a magnetic field be involved in the creation of a flow of electrons/current? Therefore is it reasonable to suggest that we can create a magnetic field by having a flow of current and this can be used to make more current? Explain how this can occur
Physics
1 answer:
olga nikolaevna [1]3 years ago
3 0

Answer:

Magnetic field can be used to produce current, infact a changing magnetic field can produce current.

A changing magnetic field in a loop causes the flux linked with the loop to change in turn generating a emf in the loop and therefore a current.

For a loop of area A and resistance R.

I =dPhi/dt/R

В. А

I = AcosФ/R .dB /dt

But it isn't reasonable to say that we can create a magnetic field by having a flow of current and this can be used to make more current because the current generated due to change in magnetic field created by increase/decrease in flow of current will be in a direction such that it will counter act the change in magnetic field caused by increase/decrease in current flow.(lenz's law).

We were unable to transcribe this image

Ф= В. А

I = Acos dB Rd

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3 years ago
Read 2 more answers
The suspension system of a 2100 kg automobile "sags" 8.5 cm when the chassis is placed on it. Also, the oscillation amplitude de
Gennadij [26K]

Answer:

Part a)

k = 6.06 \times 10^4 N/m

Part b)

b = 1795.4 kg/s

Explanation:

Part a)

as the mass of the suspension system is given as

m = 2100 kg

also we have

x = 8.5 cm

so now for force balance we have

mg = kx

(525)(9.81) = k(0.085)

k = 6.06 \times 10^4 N/m

Part b)

Now we know that amplitude decreases by 63% in each cycle

so after one cycle the amplitude will become 37% of initial amplitude

so it is given as

A = 0.37 A_o

also we know

A = A_o e^{-bt/2m}

0.37 A_o = A_o e^{-bt/2m}

\frac{bt}{2m} = 1

b = \frac{2m}{t}

here t = time period of one oscillation

so it is

t = 2\pi\sqrt{\frac{m}{k}}

t = 2\pi\sqrt{\frac{525}{6.06 \times 10^4}}

t = 0.58 s

now damping constant is

b = \frac{2(525)}{0.58}

b = 1795.4 kg/s

7 0
3 years ago
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