(a) The velocity of mug was 3.10 m/s
(b) The direction of the mug's velocity just about it hit the floor is about 56.9° below the horizontal
<h3>Further explanation</h3>
Acceleration is rate of change of velocity.
<em>a = acceleration ( m/s² )</em>
<em>v = final velocity ( m/s )</em>
<em>u = initial velocity ( m/s )</em>
<em>t = time taken ( s )</em>
<em>d = distance ( m )</em>
Let us now tackle the problem!
This problem is about Projectile Motion.
<u>Given:</u>
horizontal distance = x = 1.50 m
height of the counter = h = 1.15 m
<u>Unknown:</u>
a. initial velocity = u = ?
b. direction of the mug's velocity = θ = ?
<u>Solution:</u>
<em>Question a:</em>
→ <em>Equation 1</em>
← <em>Equation 1</em>
<em>Question b:</em>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall