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Minchanka [31]
2 years ago
15

Why does the Earth exert a gravitational force on objects on its surface?

Physics
1 answer:
andre [41]2 years ago
8 0

Answer:

B. It has mass

Explanation:

The Newtons Universal gravitacion law is : F = G.\frac{m1 m2}{d^{2} }  , where <u>F</u> is the force exerted , <u>m1</u> and <u>m2</u> are the earth's mass and the object's mass, <u>d</u> is the distance and <u>G</u> the gravitacional constant. Comparing to the options we can say that the Earth exerts a gravitational force on objects on its surface because of its mass.

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The acceleration of a particle is given by a = 6t - 28, where a is in meters per second squared and t is in seconds. Determine t
baherus [9]

Answer:

Velocity, V = 3t²- 28t+6

Displacement, s = t³ - 14t²+6t -8

At t = 5.8 s

        s = -249.05 m

        v = -55.48 m/s

At t = 12.7 s

        s = -141.48 m

        v = 134.27 m/s

Explanation:

We have acceleration of a particle is given by  a = 6t - 28

Velocity

      v=\int adt=\int (6t - 28)dt=3t^2-28t+C

At t = 0 we have v₀ = 6 m/s

         v₀ = 6 =  3 x 0 ²-28 x 0+C

         C = 6

        So velocity, V = 3t² - 28t+6

Displacement

        s=\int vdt=\int (3t^2-28t+6)dt=t^3-14t^2+6t+C

At t = 0 we have s₀ = -8 m

         s₀ = -8 =  0³ + 14 x 0² + 6 x 0 + C

         C = -8

        So displacement, s = t³ - 14t²+6t -8

At t = 5.8 s

        s = 5.8³ - 14 x 5.8²+6 x 5.8 - 8 = -249.05 m

        v =  3 x 5.8² - 28 x 5.8 + 6 = -55.48 m/s

At t = 12.7 s

        s = 12.7³ - 14 x 12.7²+6 x 12.7 - 8 = -141.48 m

        v =  3 x 12.7² - 28 x 12.7 + 6 = 134.27 m/s

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The work done when a force moves a body through a distance of 15m is 1800j. What is the value of the force applied
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Answer:

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Work :

W = Fd (work = force x distance)

Force :

F = W/d

Distance :

d = W/F

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Explanation:

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Answer:

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Explanation:

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