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Minchanka [31]
3 years ago
15

Why does the Earth exert a gravitational force on objects on its surface?

Physics
1 answer:
andre [41]3 years ago
8 0

Answer:

B. It has mass

Explanation:

The Newtons Universal gravitacion law is : F = G.\frac{m1 m2}{d^{2} }  , where <u>F</u> is the force exerted , <u>m1</u> and <u>m2</u> are the earth's mass and the object's mass, <u>d</u> is the distance and <u>G</u> the gravitacional constant. Comparing to the options we can say that the Earth exerts a gravitational force on objects on its surface because of its mass.

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The loudness of a sound is the waves amplitude <br><br><br><br> True or false
kakasveta [241]

Answer:

true i think

Explanation:

The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound. In Figure 10.2 sound C is louder than sound B. The vibration of a source sets the amplitude of a wave.

4 0
3 years ago
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4. Many of the teachers think that if a student sleeps more on the night before the test, then they
Effectus [21]

Answer:

a sleep doesnt get to depict whether you get a good grade or not its what you know.

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1 year ago
A "spherical capacitor" is constructed of two thin, concentric spherical shells of conducting material. Let a be the radius of t
Shalnov [3]

Answer:

C=\frac{ab}{k(b-a)}

Explanation:

We can assume this problem as two concentric spherical metals with opposite charges.

We have also to take into account the formulas for the electric field and the capacitance. Hence we have

C=\frac{Q}{V}\\\\E=k\frac{Q}{r^2}\\

Where k is the Coulomb's constant. Furthermore, by taking into account the expression for the potential and by integrating

dV=Edr\\\\V=\int_{R_1}^{R_2}Edr=-\int_{R_1}^{R_2}\frac{kQ}{r^2}dr\\\\V=kQ[\frac{1}{R_2}-\frac{1}{R_1}]

Hence, the capacitance is

C=\frac{1}{k[\frac{1}{R_2}-\frac{1}{R_1}]}

but R1=a and R2=b

C=\frac{ab}{k(b-a)}

HOPE THIS HELPS!!

3 0
3 years ago
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If a 2 x 10^-4C test charge is given 6.5J of energy, determine the electric potential difference.
Gwar [14]

Answer:

The electric potential difference is 32500 volt.

Explanation:

Given that,

Chargeq=2\times10^{-4}C

Energy = 6.5 J

We need to calculate the electric potential difference

Potential difference :

Potential difference is equal to the energy divide by charge.

Using formula of potential difference

V=\dfrac{E}{Q}

V=\dfrac{6.5}{2\times10^{-4}}

V=32500\ volt

Hence, The electric potential difference is 32500 volt.

8 0
3 years ago
Parallel Circuits:
Ber [7]

Answer:

D.)

Explanation:

the current separates on each branch according to the resistance it experience.

8 0
3 years ago
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