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Minchanka [31]
2 years ago
15

Why does the Earth exert a gravitational force on objects on its surface?

Physics
1 answer:
andre [41]2 years ago
8 0

Answer:

B. It has mass

Explanation:

The Newtons Universal gravitacion law is : F = G.\frac{m1 m2}{d^{2} }  , where <u>F</u> is the force exerted , <u>m1</u> and <u>m2</u> are the earth's mass and the object's mass, <u>d</u> is the distance and <u>G</u> the gravitacional constant. Comparing to the options we can say that the Earth exerts a gravitational force on objects on its surface because of its mass.

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What would happen if you put a material between each marble? Newton's Cradle
slamgirl [31]

Answer:

Explanation:

Momentum is the mass of a moving body times its velocity. It can be transferred from one object to another

5 0
2 years ago
As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. Th
NikAS [45]

Answer:

M = 0.730*m

V = 0.663*v

Explanation:

Data Given:

v_{bullet, initial} = v\\v_{bullet, final} = 0.516*v\\v_{paper, initial} = 0\\v_{paper, final} = V\\mass_{bullet} = m\\mass_{paper} = M\\Loss Ek = 0.413 Ek

Conservation of Momentum:

P_{initial} = P_{final}\\m*v_{i} = m*0.516v_{i} + M*V\\0.484m*v_{i} = M*V .... Eq1

Energy Balance:

\frac{1}{2}*m*v^2_{i} = \frac{1}{2}*m*(0.516v_{i})^2 + \frac{1}{2}*M*V^2 + 0.413*\frac{1}{2}*m*v^2_{i}\\\\0.320744*m*v^2_{i} = M*V^2\\\\M = \frac{0.320744*m*v^2_{i} }{V^2}  ....... Eq 2

Substitute Eq 2 into Eq 1

0.484*m*v_{i} = \frac{0.320744*m*v^2_{i} }{V^2} *V  \\0.484 = 0.320744*\frac{v_{i} }{V} \\\\V = 0.663*v_{i}

Using Eq 1

0.484m*v_{i} = M* 0.663v_{i}\\\\M = 0.730*m

7 0
3 years ago
What is the energy equivalent of an object with a mass of 1.83 kg?
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E = 1.83 kg (3x10^8 m/s)^2
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6 0
2 years ago
Read 2 more answers
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Korvikt [17]

You have learned your lesson well, Suhay. Your statement is correct.

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7 0
3 years ago
For life to flourish on Earth, several changes occurred that affected the atmosphere, such as _____.
e-lub [12.9K]
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Are the options</span>
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