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3 years ago

Why does the Earth exert a gravitational force on objects on its surface?

Physics

1 answer:

andre [41]3 years ago

8 0

Answer:

B. It has mass

Explanation:

The Newtons Universal gravitacion law is : F = G. $\frac{m1 m2}{d^{2} }$ , where F is the force exerted , m1 and m2 are the earth's mass and the object's mass, d is the distance and G the gravitacional constant. Comparing to the options we can say that the Earth exerts a gravitational force on objects on its surface because of its mass.

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If the volume of a container increases what effect will this have on pressure? Why?

frozen [14]

As the volume of the container increases the pressure inside will decrease because the atoms have more room to move around in.

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2 years ago

Read 2 more answers

A block of 1 kg with a speed 1 m/s hits a spring placed horizontally as shown in the figure. If spring constant is 1000 N/m, fin

Evgen [1.6K]

Answer:

0.0316 m

Explanation:

Wok done = Energy change

Work done on the spring = Energy change of the block

Elastic Potential stored = Kinetic energy of the block

$\frac{1}{2} kx^{2} = \frac{1}{2} mv^{2}$

x = $\sqrt{v^{2}\frac{m}{k} }$

x = $\sqrt{1^{2}\frac{1}{1000} }$

x = 0.0316 m

k = spring constant

m = mass of block

v = velocity of the block

x = compression of spring

8 0

3 years ago

A woman fires a rifle with barrel length of 0.5400 m. Let (0, 0) be where the 125 g bullet begins to move, and the bullet travel

dybincka [34]

Answer:

Explanation:

Given that,

Length of barrel =0.54m

Mass of bullet=125g=0.125kg

Force extend

F=16,000+10,000x-26,000x²

a. Work done is given as

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=0.54m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=0.54m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=0.54m

W= 16,000(0.54) + 5000(0.54²) - 8666.667(0.54³) +0+0-0

W=8640+1458-1364.69

W=8733.31J

The workdone by the gas on the bullet is 8733.31J

b. Work done is given as

Work done when the length=1.05m

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=1.05m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=1.05m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=1.05mm

W= 16,000(1.05) + 5000(1.05²) - 8666.667(1.05³) +0+0-0

W=16800+5512.5-10032.75

W=12,279.75J

The workdone by the gas on the bullet is 12,279.75J

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3 years ago

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