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Westkost [7]
3 years ago
6

A train takes ms eaddy 200 miles north and 150 miles south. The total trip took 3.5 hours what was the average velocity of the t

rain in MPG?
Physics
1 answer:
Verizon [17]3 years ago
3 0
The whole point of this problem is to check how well you understand
the definitions of a few important quantities, like velocity, speed, distance,
displacement etc.

Before we begin, I just want to mention that 'MPG' is not a unit of either
velocity or speed, but I think I know what you mean.

-- For some reason, Ms. Eaddy rode 100 miles north on the train, then
stayed aboard while the train turned around and took her 150 miles south.
The total distance she rode was (100 + 150) = 250 miles.  But she ended up
50 miles south of where she began.

-- Displacement for the whole trip = distance and direction from the start point
to the finish point.

Displacement = 50 miles south

-- Average velocity = (displacement) / (time)

50 miles south / 3.5 hours = <u>14.29 miles per hour south</u>
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rusak2 [61]

Answer:

Spring constant in N / m = 6,000

Explanation:

Given:

Length of spring stretches = 5 cm = 0.05 m

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Find:

Spring constant in N / m

Computation:

Spring constant in N / m = Force/Distance

Spring constant in N / m = 300 / 0.05

Spring constant in N / m = 6,000

8 0
2 years ago
Wilma can mow a lawn in 80 minutes. Rocky can mow the same lawn in 120 minutes. Construct an equation that would allow you to de
xeze [42]

Answer:

t = 96 minutes

Explanation:

Time to mow 1 lawn by Wilma is 80 minutes

so work done in 1 minute by Wilma is given as

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Similarly Rocky mow same lawn in 120 minute

so work done in 1 minute by Rocky is given as

W_2 = \frac{1}{120}

now we know that they both worked by "t" time

so total work performed by them

W = \frac{t}{80} + \frac{t}{120}

they both mow 2 lawns then it is given as

2 = (\frac{1}{80} + \frac{1}{120})t

t = 96 minutes

5 0
3 years ago
An 7.5 × binocular has 3.7-cm-focal-length eyepieces. What is the focal length of the objective lenses? Express your answer to t
elixir [45]

To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,

\mu = \frac{f_0}{f_e}

Here,

\mu = Magnification

f_e = Focal length eyepieces

f_0 = Focal length of the Objective

Rearranging to find the focal length of the objective

f_0 = \mu f_e

Replacing with our values

f_0 = 7.5* 3.7cm

f_0 = 27.75cm

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3 years ago
Which two pieces of evidence most directky support the idea that all matter in the universe began as a sibgke point of energy.
Aleks04 [339]

Answer:

YOUR ANSWER IS GIVEN BELOW:

Explanation:

The abundance of helium in the universe and the redshift of light from the galaxies.

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2 years ago
What is the definition of Mutualism
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3 years ago
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