Answer:
0.292 g/mL.
Explanation:
From the question given above, the following data were obtained:
Mass of object = 28.1 g
Volume of object = 96.2 mL
Density of object =..?
Density of an object is simply defined as the mass of the object per unit volume of the object. Mathematically, it can be expressed as:
Density = mass / volume
With the above formula, we can obtain the density of the object as follow:
Mass of object = 28.1 g
Volume of object = 96.2 mL
Density of object =..?
Density = mass / volume
Density = 28.1 / 96.2
Density of object = 0.292 g/mL
Thus the density of the object is 0.292 g/mL
A student compares the boiling point of substances having different intermolecular forces. <u>Boiling points of various substances</u> is the dependent variable that student most likely use.
<h3>Does the nature of intermolecular forces present in different substance affect their boiling points?</h3>
The boiling point of a substance is proportional to the strength of its intermolecular forces, the higher the boiling point, the stronger the intermolecular forces. We can compare the strengths of intermolecular forces by comparing the boiling points of different substances.
<h3>What properties are affected by intermolecular forces?</h3>
Intermolecular forces are measured by boiling points.
Intermolecular forces increase as bond polarization increases.
Ionic > hydrogen bonding > dipole dipole > dispersion is the order of the strength of intermolecular forces (and thus their impact on boiling points).
<h3>How can you determine strong and weak intermolecular forces?</h3>
Substances with strong intermolecular forces are very attracted to one another and are held together tightly. These substances require a great deal of energy to separate, whereas substances with weak intermolecular forces are held together very loosely and have weak interactions.
Learn more about intermolecular forces:
<u><em>brainly.com/question/13479228</em></u>
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Answer:
-304.1
Explanation:
Just took it on Edge 2020
Answer: 16700 Joules
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat absorbed = ?
m = mass of sand = 2 kg
c = heat capacity = 
Initial temperature = 
= 
Final temperature= 
= 
Change in temperature ,
Putting in the values, we get:
16700 J of energy must be added to a 2-kilogram pile of it to increase its temperature from 40°C to 50°C
Answer:
The answer to your question is below
Explanation:
Data
mass of CaCO₃ = 155 g
mass of HCl = 250 g
mass of CaCl₂ = 142 g
reactants = CaCO₃ + HCl
products = CaCl₂ + CO₂ + H₂O
1.- Balanced chemical reaction
CaCO₃ + 2HCl ⇒ CaCl₂ + CO₂ + H₂O
2.- Limiting reactant
molar mass of CaCO₃ = 40 + 12 + 48 = 100 g
molar mass of HCl = 2[1 + 35.5 ] = 73 g
theoretical proportion CaCO₃ /HCl = 100 / 73 = 1.37
experimental proportion CaCO₃ /HCl = 155 / 250 = 0.62
As the experimental proportion was lower than the theoretical proportion the limiting reactant is CaCO₃
3.-
Calculate the molar mass of CaCl₂
CaCl₂ = 40 + 71 = 111 g
100 g of CaCO₃ ------------------ 111 g of CaCl₂
155 g of CaCO₃ ----------------- x
x = (155 x 111) / 100
x = 17205 / 100
x = 172.05 g of CaCl₂
4.- percent yield
Percent yield = 142 / 172.05 x 100 = 82.5 %
5.- Excess reactant
100 g of CaCO₃ -------------------- 73 g of HCl
155 g of caCO₃ ------------------- x
x = (155 x 73)/100
x = 133.15 g
Mass of HCl = 250 - 133.15
= 136.9 g
