1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
myrzilka [38]
3 years ago
8

During a synthesis reaction, 1.8 grams of magnesium reacted with 6.0 grams of oxygen. What is the maximum amount of magnesium ox

ide that can be produced during the reaction? Mg + O2 → MgO 2.2 grams 2.9 grams 3.4 grams 3.9 grams
Chemistry
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

2.9 grams.

Explanation:

  • From the balanced reaction:

<em>Mg + 1/2O₂ → MgO,</em>

1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.

  • We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:

no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.

no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.

<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1.0 mole of Mg produce → 1.0 mol of MgO.

∴ 0.074 mol of Mg produce → 0.074 mol of MgO.

<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.074 mol)(40.3 g/mol) = <em>2.98 g.</em>

You might be interested in
What is oxidized in a galvanic cell with aluminum and gold electrodes ?
k0ka [10]

Answer:

Aluminum metal

Explanation:

In order to properly answer this or a similar question, we need to know some basic rules about galvanic cells and standard reduction potentials.

First of all, your strategy would be to find a trusted source or the table of standard reduction potentials. You would then need to find the half-equations for aluminum and gold reduction:

Al^{3+}+3e^-\rightarrow Al; E^o=-1.66 V

Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Since we have a galvanic cell, the overall reaction is spontaneous. A spontaneous reaction indicates that the overall cell potential should be positive.

Since one half-equation should be an oxidation reaction (oxidation is loss of electrons) and one should be a reduction reaction (reduction is gain of electrons), one of these should be reversed.

Thinking simply, if the overall cell potential would be obtained by adding the two potentials, in order to acquite a positive number in the sum of potentials, we may only reverse the half-equation of aluminum (this would change the sign of E to positive):Al\rightarrow Al^{3+}+3e^-; E^o=1.66 V\\Au^{3+}+3e^-\rightarrow Au; E^o=1.50 V

Notice that the overall cell potential upon summing is:

E_{cell}=1.66 V + 1.50 V=3.16 V

Meaning we obey the law of galvanic cells.

Since oxidation is loss of electrons, notice that the loss of electrons takes place in the half-equation of aluminum: solid aluminum electrode loses 3 electrons to become aluminum cation.

6 0
3 years ago
The Electrical conductivity of an aqueous solution depends on the concentration of which particles in the solution
anyanavicka [17]
It depends on the concentration of ions which are responsible for the electrical conductivity in aqueous solutions.
6 0
3 years ago
Read 2 more answers
Identify which of the following descriptions of a tree is quantitative?
sattari [20]

Answer:

b) has leaves that are 8 -10 cm long

8 0
3 years ago
Read 2 more answers
A substance with a high [h ] would likely have which additional characteristics?
Ray Of Light [21]

Answer:

Is [h] really [H]?  What characteristics are mentioned?

Explanation:

A high [H} means high acid concentration.  

6 0
2 years ago
Write the balanced COMPLETE ionic equation for the reaction when aqueous NiCl₂ and aqueous Na₂S are mixed in solution to form so
Reptile [31]

Answer:

Explanation:

The chemical reaction of the well-balanced equation is as follows:

\mathbf{2NiCl_{2(aq)}+2Na_2S_{(aq)} \to 4NaCl_{(aq)}+2NiS_{s}}

The aforementioned reaction's ionic equation is:

\mathbf{2Ni^{2+}_{(aq)}+4Cl^-_{(aq)}+ 4Na^+_{(aq)}+2S^{2-}_{(aq)} \to 4Na^+_{(aq)}+4Cl^-_{(aq)}+2NiS_{(s)}}

From above; Na⁺ and Cl⁻ appear on both sides;

Hence, the net ionic equation is:

\mathbf{2Ni^{2+}_{(aq)}+2S^{2-}_{(aq)} \to 2NiS_{(s)}}

3 0
3 years ago
Other questions:
  • “Copper nitrate is a” <br><br> Symbol <br><br> Name <br><br> Chemical formula
    14·2 answers
  • Earth's original atmosphere probably consisted mostly of which gas?
    12·1 answer
  • How many milliliters of 2.15 wt% dimethylglyoxime solution should be used to provide a 50.0% excess for Reac- tion 7-2 with 0.99
    8·1 answer
  • Noz at
    7·1 answer
  • Sodium bicarbonate is the chemical name for baking soda. Its chemical formula is NaHCO3. What does the subscript 3 mean?
    12·2 answers
  • HELP PLEASEEEEE KAJAMAAKAOAAJAKAKJSMALASJSSJKSSKSJSMKSLWWMSMSKLSSLSKSMMSMSKSKSOSKSSMMSMSKSKSSKMSMSMSMSKSMMSNSSMMSMSMSMSMSKSKSLSL
    11·1 answer
  • Using PEP or PrEP can reduce the chances of becoming infected for a person exposed to HIV.
    10·2 answers
  • Italian dressing contains olive oil and vinegar, which will separate out from each other if left to sit. This makes the dressing
    10·1 answer
  • Kate gathered three boxes of the same size made of different materials; glass, clear
    8·1 answer
  • Write the chemical formula for tin(ii)sulfite.. Please show working thank you
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!