Volume= Mass/ Density= 20/184
= 0.108 cubic cm
Answer:0.300M
Explanation:1) Data:
a) Initial solution
M = 1.50M
V = 50.0 ml = 0.050 l
b) Solvent added = 200 ml = 0.200 l
2) Formula:
Molarity: M = moles of solute / volume of solution is liters
3) Solution:
a) initial solution:
Clearing moles from the molarity formula: moles = M × V
moles of H₂SO₄ = M × V = 1.5M × 0.050 l = 0.075 mol
b) final solution:
i) Volumen of solution = 0.050 l + 0.200l = 0.250l
ii) M = 0.075 mol / 0.250 l = 0.300M ← answeer
<h3>1.<u> Answer;</u></h3>
False
<h3><u>Explanation;</u></h3>
Bases have some of the following properties;
- They have a bitter taste
- They have a slimy, or soapy feel on fingers
- Most bases react with acids and precipitate salts.
- Strong bases may react violently with acids.
- Bases turn red litmus paper blue
<h3>2. <u>Answer;</u></h3>
An acid
<h3><u>Explanation;</u></h3>
- When acids are dissolved in water, the concentration of the acid decreases and it becomes dilute.
- It dissociates in water to give H+ ions or hydrogen ions.
- All acidic solutions contain more hydrogen ions than hydroxide ions, therefore when added to water it increases the concentration of H+ ions in water, as water is a neutral substance whose concentration of H+ ions is equal to OH-.
The molecular formula for hyponitrous acid is H2N2O2. and for nitroxyl is HNO.
The chemical compound HNO is also known as nitroxyl (common name) or Azanon (IUPAC name). In the gas phase, it is widely recognized. In the solution phase, the short-lived intermediate nitroxyl can develop. Nitric oxide (NO) is reduced to form the conjugate base, NO, which is isoelectronic with dioxygen.
By oxidizing hydroxylamine with CuO , HgO, and Ag 2 and by oxidizing hydroxylamine with N2O3 in methyl-alcoholic solution, we can create hyponitrous acid.
Learn more about chemical compound here -
brainly.com/question/12166462
#SPJ4
I believe it's about the dislodging response as Ag structures solvent salt with nitrate. For dislodging response, more receptive metal will uproot less receptive metal from the arrangement. In your question, the reactivity of the metal are positioned as takes after: Mg > Cu > Ag. Take note of that more responsive metals, that are Mg and Cu, are in the arrangement.
