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sashaice [31]
3 years ago
5

How do you have factor y=6x²+24x-192 and find the zeros?

Mathematics
1 answer:
zvonat [6]3 years ago
3 0
y=6x^2+24x-192\\\\y=0\ \ \ \Leftrightarrow\ \ \ 6x^2+24x-192=0\ /:6\\\\x^2+4x-27=0\\\\x^2+2\cdot2\cdot x+2^2-2^2-27=0\\\\(x+2)^2-31=0\\\\(x+2)^2=31\ \ \ \Leftrightarrow\ \ \ (x+2= \sqrt{31} \ \ \ or\ \ \ x+2=- \sqrt{31})\\\\x=-2+ \sqrt{31}\ \ \ or\ \ \ x=-2- \sqrt{31}
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labwork [276]

Answer:

1. UW // TX

2. VX // UY

3. UW ≅ TY ≅ YX

4. YW = \frac{1}{2} TV

5. TX = 2 UW

6. ∠TXV ≅∠WUY

Step-by-step explanation:

The line segment joining the midpoint of two sides of a triangle is parallel to the third side and equal to half its length

In Δ XVT

∵ U is the midpoint of VT

∵ W is the midpoint of VX

∵ XT is the 3rd side of the triangle

→ By using the rule above

∴ UW // TX ⇒ (1)

∴ UW = \frac{1}{2} TX

→ Multiply both sides by 2

∴ 2 UW = TX

∴ TX = 2 UW ⇒ (5)

∵ Y is the midpoint of TX

∴ TY = YX = \frac{1}{2} TX

∵ UW = \frac{1}{2} TX

∴ UW ≅ TY ≅ YX ⇒ (3)

∵ U is the midpoint of VT

∵ Y is the midpoint of XT

∵ VX is the 3rd side of the triangle

→ By using the rule above

∴ UY // VX

∴ VX // UY ⇒ (2)

∴ UY = \frac{1}{2} VX

∵ W is the midpoint of VX

∵ Y is the midpoint of XT

∵ TV is the 3rd side of the triangle

→ By using the rule above

∴ YW // TV

∴ YW = \frac{1}{2} TV ⇒ (4)

∵ 2 Δs UYW and XVT

∵ UY = \frac{1}{2} XV

∵ YW = \frac{1}{2} VT

∵ WU = \frac{1}{2} TX

∴ \frac{UY}{XV} = \frac{UW}{VT} = \frac{WU}{TX} = \frac{1}{2}

→ By using the SSS postulate of similarity

∴ ∠TXV ≅∠WUY ⇒ (6)

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Step-by-step explanation:

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