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sashaice [31]
3 years ago
5

How do you have factor y=6x²+24x-192 and find the zeros?

Mathematics
1 answer:
zvonat [6]3 years ago
3 0
y=6x^2+24x-192\\\\y=0\ \ \ \Leftrightarrow\ \ \ 6x^2+24x-192=0\ /:6\\\\x^2+4x-27=0\\\\x^2+2\cdot2\cdot x+2^2-2^2-27=0\\\\(x+2)^2-31=0\\\\(x+2)^2=31\ \ \ \Leftrightarrow\ \ \ (x+2= \sqrt{31} \ \ \ or\ \ \ x+2=- \sqrt{31})\\\\x=-2+ \sqrt{31}\ \ \ or\ \ \ x=-2- \sqrt{31}
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What is the range of the given data set?
user100 [1]

Answer:

6

Step-by-step explanation:

21 - 15 = 6

6 0
2 years ago
Ill give brainiest<br><br> if it was 11:30 am and its now 11:47 am, how many hours was that
Kaylis [27]

Answer:

0 hours and 17 minutes

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6 0
3 years ago
Find the values of x and y that make these triangles congruent by the HL Theorem.
RideAnS [48]

According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

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By using equation (1) next step is to plug in y+1 for x in equation (2). So,

2 ( y + 1) + 3 = 3y + 3

2y + 2 + 3 = 3y + 3 By using distribution property.

2y + 5 = 3y + 3

2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.

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So, y=2

Next step is to plug in y=2 in equation (1) to get the value of x. Hence,

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7 0
3 years ago
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seropon [69]

Answer:

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Explanation:

1. Line Q is defined as a slope of \frac{5}{3}; i.e. y=\frac{5}{3}

2. Line R is defined to be parallel of Line Q.

3. Line Q is linear and has no domain restrictions.

The definition of being parallel requires the same slope.

5 0
2 years ago
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Mashcka [7]
False
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4 0
3 years ago
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