Assignment Explain why it is not advisable to wear black silky cloth in the sun

1.29 g piece of lead has a temperature of 26.0 °C. If it loses 1.90 J of heat to its surroundings, what is its new temperature.

malfutka [58]

The new temperature of the piece of lead will be 37.5°C

SPECIFIC HEAT CAPACITY:

The amount of heat absorbed or released by a substance can be calculated by using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed or released (J)

m = mass of substance (g)

c = specific heat capacity

∆T = change in temperature (°C)

According to this question,

Q = 1.90J

m = 1.29g

T1 = 26°C

T2 = ?

c = 0.128 J/g°C

1.90 = 1.29 × 0.128 × (T2- 26°C)

1.90 = 0.165 (T2 - 26°C)

1.90 = 0.165T2 - 4.29

1.90 + 4.29 = 0.165T2

6.19 = 0.165T2

T2 = 37.5°C

Therefore, the new temperature of the piece of lead will be 37.5°C.

Learn more: brainly.com/question/20514651?referrer=searchResults

5 0

2 years ago

You are trying to determine how

ss7ja [257]

Answer:

0,218 moles

Explanation:

I will first explain how many liters is 256ml, that is 0,256 l.

because the m stands for milli which is a factor of 1000 -> (256 ml / 1000 = 0,256 l)

To calculate the amount of moles you multiply the volume with the concentration. So 0,256l x 0,855M = 0,218 moles.

5 0

1 year ago

The solid part of the blood consists of _____ and _____ blood cells.

Aloiza [94]

Your blood is a living part or tissue of your body that composed of liquid and solid part. The liquid part is made of plasma and mineral like, water, salt and protein. While the solid part is composed of red blood cells, white blood cells and also platelets

8 0

3 years ago

The retina of a human eye can detect light when radiant energy incident on it is at least 4.00 × 10−17 J. For light of 535−nm wa

VLD [36.1K]

Answer:

1080 photons

Explanation:

ΔE = hc/λ => Energy per photon

h = 6.63 x 10⁻³⁴ j·s

c = 3 x 10⁸ m/s

λ= 535 nm = 5.35 x 10⁻⁷ m

ΔE/photon = (6.63 x 10⁻³⁴ j·s)(c = 3 x 10⁸ m/s)/(5.35 x 10⁻⁷ m) = 3.71 x 10⁻¹⁹ j/photon

For #photons in 4.00 x 10⁻⁷ j = (4.00 x 10⁻⁷ j) / (3.71 x 10⁻¹⁹ j/photon) = 1076 photons ≅ 1080 photons (3 sig. figs.)

7 0

3 years ago

What is the standard cell notation for a galvanic cell made with silver and nickel?

MA_775_DIABLO [31]

Answer:

Ni(s)∣∣Ni2+(aq) ∣∣∣∣ Ag+(aq)∣∣Ag(s)

Explanation:

Start by finding the standard reduction potential for the Ag+ and Ni2+ ion. Normally, the values are listed at the back of most chemistry textbooks.

Ag+(aq)+1e−→Ag(s) Eo=0.80 V
Ni2+(aq)+2e−→Ni(s) Eo=−0.23 V

In the galvanic cell, the reaction is spontaneous and for a spontaneous reaction Eocellmust be a positive quantity.

Eocell=EoAnode+Eocathode

Manipulate the two equations so that Eocell is positive. Note that the anode is the site of oxidation (where electrons are lost) and the cathode (where electron are gained) is the site for reduction.

Ag+(aq)+1e−→Ag(s) Eo=0.80 V
Ni(s)→Ni2+(aq)+2e− Eo=0.23 V

2×{Ag+(aq)+1e−→Ag(s)} Eo=0.80 V (Cathode)
Ni(s)→Ni2+(aq)+2e− Eo=0.23 V (Anode)
 −−−
2Ag+(aq)+Ni(s)→Ni2+(aq)+2Ag(s) Eocell=1.03 V

Start with the anode components (site of oxidation) - the cathode components are listed to the right.

Ni(s)∣∣Ni2+(aq) ∣∣∣∣ Ag+(aq)∣∣Ag(s)

The single vertical lines indicate the boundary (phase difference) between solid Niand Ni2+ ions in the aqueous solution of the first compartment and between solid Ag and Ag+ ions present in the aqueous solution of the second compartments.

The double vertical lines refer to the salt bridge - note that the salt bridge must be an inert salt to both ions present in both compartments of the galvanic cell ...

5 0

3 years ago

AssignmentExplain why it is not advisable to wearblack silky cloth in the sun​

AssignmentExplain why it is not advisable to wearblack silky cloth in the sun