The voltage at the end of the conductors is 12V
<u>Explanation:</u>
Given:
Resistance, R = 12Ω
Heat released, H = 144J
Time, t = 12s
Voltage, V = ?
According to joule's law:
H = I²RT
where,
I is the current
T is the time
R is the resistance
The above formula can also be written as:
where,
V is the voltage
On substituting the value in the formula we get:
Therefore, the voltage at the end of the conductors is 12V
Answer:
Explanation:
1 ) Let the initial horizontal velocity of car be v .
For vertical displacement
vertical displacement h = 21.3 - 2.3 = 19 m
Time taken to fall by 19 m be t
19 = 1/2 x 9.8 t² ( initial downward velocity is zero )
t = 1.97 s
This is also the time taken to cover horizontal displacement of 54 m which is width of river .
horizontal speed v = 54 / 1.97 m /s
v = 27.41 m /s
2 )
At the time of landing on other side , car will have both vertical and horizontal speed .
vertical speed
v = u + gt
= 0 + 9.8 x 1.97 = 19.31 m /s
horizontal speed will remain same as the initial speed = 27.41 m /s
Resultant speed = √ ( 27.41² + 19.31² )
= √ ( 751.3 + 372.87)
= 33.52 m /s
Because the Earth<span> is a sphere, the surface gets much more intense </span>sunlight<span>, hence heat, at </span>the equator<span>than at the poles.</span>
The net force on the car for either case will be zero, since the car is moving at a constant velocity.
<h3>Net force on the car</h3>
The net force on the car is the sum of all the forces acting on the car.
∑F = ma
<h3>When the car is on a level road</h3>
When the car is on a level road, the only two forces acting on the car is the applied force and frictional force of the road.
F - Ff = 0
The net force will be zero, since the car is moving at a constant velocity.
<h3>When the car is on uphill</h3>
The forces acting on the car at the uphill is the applied force, weight of the car acting downwards and the frictional force acting opposite direction.
F - Wsinθ - μFₙcosθ = 0
The net force will be zero, since the car is moving at a constant velocity.
Learn more about net force at constant velocity here: brainly.com/question/14392124
Answer:
Explanation:
Force of friction at car B ( break was applied by car B ) =μ mg = .65 x 2100 X 9.8 = 13377 N .
work done by friction = 13377 x 7.30 = 97652.1 J
If v be the common velocity of both the cars after collision
kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²
= 1800 v²
so , applying work - energy theory ,
1800 v² = 97652.1
v² = 54.25
v = 7.365 m /s
This is the common velocity of both the cars .
To know the speed of car A , we shall apply law of conservation of momentum .Let the speed of car A before collision be v₁ .
So , momentum before collision = momentum after collision of both the cars
1500 x v₁ = ( 1500 + 2100 ) x 7.365
v₁ = 17.676 m /s
= 63.63 mph .
( b )
yes Car A was crossing speed limit by a difference of
63.63 - 35 = 28.63 mph.