LakalakalalamLlalaa hahahaha
Recall that
![{v_f}^2-{v_i}^2=2a\Delta x](https://tex.z-dn.net/?f=%7Bv_f%7D%5E2-%7Bv_i%7D%5E2%3D2a%5CDelta%20x)
where
and
are initial and final velocities, respectively;
is acceleration; and
is the net displacement, or distance if the object is moving in a single direction.
The car has initial speed 20 m/s and acceleration -3.25 m/s². It comes to a stop, so it has 0 final speed. Then
0² - (20 m/s)² = 2 (-3.25 m/s²) ∆<em>x</em>
∆<em>x</em> = (20 m/s)² / (7.5 m/s²) ≈ 53.3 m
Answer:
B and D ( not absolutety sure though)