LakalakalalamLlalaa hahahaha
Recall that
where and are initial and final velocities, respectively; is acceleration; and is the net displacement, or distance if the object is moving in a single direction.
The car has initial speed 20 m/s and acceleration -3.25 m/s². It comes to a stop, so it has 0 final speed. Then
0² - (20 m/s)² = 2 (-3.25 m/s²) ∆<em>x</em>
∆<em>x</em> = (20 m/s)² / (7.5 m/s²) ≈ 53.3 m
Answer:
B and D ( not absolutety sure though)