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2 years ago

for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it

Physics

1 answer:

Ilia_Sergeevich [38]2 years ago

8 0

Answer:

O²⁻

Explanation:

Number of protons = 8

Number of neutrons = 9

Number of electrons = 10

What type of atom or ion is it = ?

Solution:

Protons are the positively charged particle in an atom

Neutrons do not carry any charges

Electrons are negatively charged particles

For this atom, the number of protons helps to identify what specie it is; so this is an oxygen atom.

Now,

Charge = Number of protons - Number of electrons

Charge = 8 - 10 = -2

The charge on the atom is -2 and so it is an oxygen ion with -2 charge

The ion is O²⁻

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Explanation:

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2 years ago

an object at rest has no ________ energy, but it may have ________ energy resulting from its location or structure.

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Answer: first blank: kinetic

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Explanation:

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5 0

2 years ago

An electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric

8090 [49]

Answer:

1.) 11 km/s

2.) 9.03 × 10^-5 metres

Explanation:

Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.

Electron q = 1.6×10^-19 C

Electron mass = 9.11×10^-31 Kg

(a) What is the speed of the electron 1.3 ns after entering this region?

E = F/q

F = Eq

Ma = Eq

M × V/t = Eq

Substitute all the parameters into the formula

9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19

V = 7.68×10^-18 /7.0×10^-22

V = 10971.43 m/s

V = 11 Km/s approximately

(b) How far does the electron travel during the 1.3 ns interval?

The initial velocity U = 64 km/s

S = ut + 1/2at^2

S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2

S =8.32×10^-5 + 7.13×10^-6

S = 9.03 × 10^-5 metres

3 0

2 years ago

A body with mass 4 kg moves with a velocity of 108km/h <br> Calculate it kinetic<br> energy

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Explanation:

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4 0

3 years ago

A straight wire 0.10 m long carrying a current of 2.0 A is at right angles to a magnetic field. The force on the wire is 0.04 N.

Vladimir79 [104]

Answer:

The strength of magnetic field is 0.2 Tesla.

Explanation:

Data from the question is

Length (L) of wire ; L=0.10 m

Current in wire ; I= 2.0 A

Force on wire ; F = 0.04 N

Angle = Right angle So, $\theta$ $\thita = 90^{o}$

Now ,

We have to find the magnetic Field strength (B)

For this formula for Force on wire in magnetic field is

$F = I \times B \times L \times sin(\theta)$

Further modified as

$B = \frac{F}{I \times L \times sin(\theta)}$

Now insert values in the formula

$B = \frac{0.04N}{2.0A \times 0.10 m \times sin(90^{0})}$

$B = 0.2 T$

So, the strength of magnetic field is 0.2 Tesla.

8 0

3 years ago

for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it​

for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it