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LekaFEV [45]
3 years ago
14

for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it​

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

Answer:

O²⁻

Explanation:

Number of protons  = 8

Number of neutrons  = 9

Number of electrons  = 10

What type of atom or ion is it = ?

Solution:

Protons are the positively charged particle in an atom

Neutrons do not carry any charges

Electrons are negatively charged particles

 For this atom, the number of protons helps to identify what specie it is; so this is an oxygen atom.

Now,

     Charge  = Number of protons  - Number of electrons

      Charge  =  8  - 10  = -2

The charge on the atom is -2 and so it is an oxygen ion with -2 charge

 The ion is O²⁻

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Answer:

100 368 J

Explanation:

Heat lost by the water = heat gained by the air ( which the 'frige works to expel and keep at 4 degrees)

specific heat for water ( in joules) :  4182 J / kg-C

    3 kg *  4182 J / kg-C  * (12-4 C) = 100 368 J

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Something that allows electrons to flow easily through it is called
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3 years ago
Read 2 more answers
1. A heat engine operates between two reservoirs at T2 = 600 K and T1 = 350 K. It takes in 1.00 x 103 J of energy from the highe
Alex73 [517]

Answer:

\Delta S_u=2.1429\ J.K^{-1}

W_c=416.67\ J

Explanation:

Given:

temperature of source reservoir, T_H=600\ K

temperature of sink reservoir, T_L=350\ K

energy absorbed from the source, Q_{in}=1000\ J

work done, W=250\ J

a.

<u>Now change in entropy of the surrounding:</u>

\Delta S_u=\frac{dQ_L}{T_L}

<em>Since heat engine is a device that absorbs heat from a high temperature reservoir and does some work giving out heat in the universe as the byproduct.</em>

\Delta S_u=\frac{Q_H-W}{T_L}

\Delta S_u=\frac{1000-250}{350}

\Delta S_u=2.1429\ J.K^{-1}

b.

<u>We know Carnot efficiency is given as:</u>

\eta_c=1-\frac{T_L}{T_H}

\eta_c=1-\frac{350}{600}

\eta_c=0.4167

<u>Now the Carnot work done:</u>

W_c=Q_H\times \eta_c

W_c=1000\times 0.4167

W_c=416.67\ J .......................(1)

c.

From eq. (1) we have the Carnot work, so the difference:

\Delta W=W_c-W

\Delta W=416.67-250

\Delta W=166.67\ J

Now, we find:

T_L.\Delta S_u=350\times 2.1429

5 0
3 years ago
(c) Another spring has a spring constant of 250 N/m.
vovikov84 [41]
It is E=something which leases another something equaling another something
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3 years ago
The work function for silver is 4.73 eV. (a) Convert the value of the work function from electron volts to joules.
pogonyaev

Answer:

W=7.56\times 10^{-19}\ J

Explanation:

Given that,

The work function for silver is 4.73 eV.

We need to find the value of the work function from electron volts to joules.

We know that,

1\ eV=1.6\times 10^{-19}\ J

For 4.73 eV,

4.73\ eV=1.6\times 10^{-19}\times 4.73\\\\=7.56\times 10^{-19}\ J

So, the work function for silver is 7.56\times 10^{-19}\ J.

6 0
3 years ago
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