I had this same problem maybe we need to work together on this
C = n/V
n = C×V
n = 4,41M × 1,25L
n = 5,5125 mol
mKI: 39+127 = 166 g/mol
1 mol --------- 166g
5,5125 mol --- X
X = 166×5,5125 = 915,075g KI
:)
Answer:
Cathode rays are streams of electrons observed in discharge tubes. In 1897, British physicist J. J. Thomson showed that cathode rays were composed of a previously unknown negatively charged particle, which was later named the electron. Cathode-ray tubes (CRTs) use a focused beam of electrons deflected by electric or magnetic fields to render an image on a screen.
<u>Answer:</u> The given sample of water is not safe for drinking.
<u>Explanation:</u>
We are given:
Concentration of fluorine in water recommended = 4.00 ppm
ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.
To calculate the ppm of fluorine in water, we use the equation:
![\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6](https://tex.z-dn.net/?f=%5Ctext%7Bppm%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20solute%7D%7D%7B%5Ctext%7BMass%20of%20solution%7D%7D%5Ctimes%2010%5E6)
Both the masses are in grams.
We are given:
Mass of fluorine =
(Conversion factor: 1 g = 1000 mg)
Mass of water = 5.00 g
Putting values in above equation, we get:
![\text{ppm of fluorine in water}=\frac{0.152\times 10^{-3}}{5}\times 10^6\\\\\text{ppm of fluorine in water}=30.4](https://tex.z-dn.net/?f=%5Ctext%7Bppm%20of%20fluorine%20in%20water%7D%3D%5Cfrac%7B0.152%5Ctimes%2010%5E%7B-3%7D%7D%7B5%7D%5Ctimes%2010%5E6%5C%5C%5C%5C%5Ctext%7Bppm%20of%20fluorine%20in%20water%7D%3D30.4)
As, the calculated concentration is greater than the recommended concentration. So, the given sample of water is not safe for drinking.
Hence, the given sample of water is not safe for drinking.