Can someone help ill give 30 extra points if its right

NEED HELP ON 31,32,33..ONLY IF YOU KNOW PLEASE

enyata [817]

Answer:

31. C

32. D

33. B

Explanation:

31. A plant cell is an eukaryotic cell i.e. it contains a membrane-bound nucleus, located CENTRALLY. The nucleus is the largest organelle in the plant cell. The cell/plasma membrane bounds the cell while the chloroplast organelle (site of photosynthesis) is also located in the plant cell. Based on this description, the image in OPTION C is correct.

32. Pottasium (K) is a highly reactive group 1 element. As stated in this question, pottasium reacts vigorously with water (H2O). This reactive property of K element is due to its valence electrons. However, elements in the same group as pottasium i.e same column on the periodic table will have the same number of valence electrons, hence, will behave chemically similar. Therefore, elements in the same column as pottasium will react the same way with water.

33. A reactant is a an element/compound in a chemical reaction that gets used up to form new products. They are usually the starting materials located on the left side of any equation. In this equation shown as:

2CuO + C → 2Cu + CO2

CuO and C are the REACTANTS while Cu and CO2 are the products.

6 0

3 years ago

Calculate the density of air at 100 Deg C and 1 bar abs. Use the Ideal Gas Law for your calculation and give answer in kg/m3. Us

madam [21]

Answer:

$d=0.92\frac{kg}{m^{3}}$

Explanation:

Using the Ideal Gas Law we have $PV=nRT$ and the number of moles n could be expressed as $n=\frac{m}{M}$ , where m is the mass and M is the molar mass.

Now, replacing the number of moles in the equation for the ideal gass law:

$PV=\frac{m}{M}RT$

If we pass the V to divide:

$P=\frac{m}{V}\frac{RT}{M}$

As the density is expressed as $d=\frac{m}{V}$ , we have:

$P=d\frac{RT}{M}$

Solving for the density:

$d=\frac{PM}{RT}$

Then we need to convert the units to the S.I.:

$T=100^{o}C+273.15$

$T=373.15K$

$P=1bar*\frac{0.98atm}{1bar}$

$P=0.98atm$

$M=28.9\frac{kg}{kmol}*\frac{1kmol}{1000mol}$

$M=0.0289\frac{kg}{mol}$

Finally we replace the values:

$d=\frac{(0.98atm)(0.0289\frac{kg}{mol})}{(0.082\frac{atm.L}{mol.K})(373.15K)}$

$d=9.2*10^{-4}\frac{kg}{L}$

$d=9.2*10^{-4}\frac{kg}{L}*\frac{1L}{0.001m^{3}}$

$d=0.92\frac{kg}{m^{3}}$

5 0

4 years ago

What does analyzing data involve?

Cloud [144]

Answer:

A. Comparing trends or patterns that prove the hypothesis

Explanation:

Analyzing data involves comparing trends or patterns that prove the hypothesis. Sometimes, the trend might invalidate the hypothesis.

Data analysis is a very important process in course of experimentation.
It brings out the meaning of data and makes data useful.
Analysis involves establishing patterns from a given set of data.
The main aim of data analysis is to identify useful information.
It usually entails cleansing and transforming data into a set that can be useful.

3 0

3 years ago

Is this a neutral atom or a charged ion ? N why

fiasKO [112]

Answer:

Explanation:

Atoms are neutral; they contain the same number of protons as electrons. A neutral sodium atom, for example, contains 11 protons and 11 electrons. Atoms that gain extra electrons become negatively charged.

8 0

3 years ago

Calculate the mass of ethylene glycol (C₂H₆O₂) that must be added to 1.00 kg of ethanol (C₂H₅OH) to reduce its vapor pressure by

Marat540 [252]

Answer:

123.5 g of C₂H₅OH are required

Explanation:

Let's think the colligative property of vapour pressure to solve this.

ΔP = P°. Xm

ΔP = Vapor pressure of pure solvent - Vapor pressure of solution

P° = Vapor pressure of pure solvent

Xm = mole fraction of solute (moles of solute / (moles of solute + moles of solvent))

11 Torr = 100 Torr . Xm

11 Torr / 100 Torr = 0.11 → Xm

0.11 = moles of solute / moles of solute + moles of solvent

Let's determine the moles of solvent.

We have a mass of 1 kg, which is the same as 1000 g

Molar mass ethanol = 46 g/mol

1000g / 46g/mol = 21.7 moles

0.11 moles = moles of solute / moles of solute +21.7 moles

0.11 moles (moles of solute +21.7 moles) = moles of solute

0.11 moles of solute + 2.39 moles = moles of solute

2.39 moles = 1 - 0.11 moles of solute

2.39 moles = 0.89 moles of solute

2.39 / 0.89 = moles of solute → 2.68 moles

Let's convert the moles to mass

2.68 moles . 46 g/mol = 123.5 g

3 0

3 years ago