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olga_2 [115]
3 years ago
12

Think About the Process In the table as x increases by​ 1, y increases by 550 . What step should you take to complete the​ table

?
X 0 1 2 3 4 5
Y 0 1650
Complete the table. Describe the relationship between x and y. Then use the table to graph the relationship.
What step should you take to complete the​ table?
A.
Subtract 550 from each value of x.
B.
Divide each value of x by 550 .
C.
Add 550 to each value of x.
D.
Multiply each value of x by 550 .
Mathematics
1 answer:
kupik [55]3 years ago
5 0

Answer:

D. Multiply

Step-by-step explanation:

Hope this helps pls give brainliest

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Answer: tough one

Step-by-step explanation:

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2 years ago
Graph the following:<br> (x - 1)2 + (y - 3)2 = 4 <br> Center<br> Radius
poizon [28]

Answer:

Center  = (1,2)  radius = 2

Step-by-step explanation:

I used Demos to graph the circle.

Then I added two line to find the center of the circle

The radius is 2

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2 years ago
The The Laplace Transform of a function , which is defined for all , is denoted by and is defined by the improper integral , as
guapka [62]

Answer:

a. L{t} = 1/s² b. L{1} = 1/s

Step-by-step explanation:

Here is the complete question

The The Laplace Transform of a function ft), which is defined for all t2 0, is denoted by Lf(t)) and is defined by the improper integral Lf))s)J" e-st . f(C)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of s as a fixed constant) 1. Find Lft) (hint: remember integration by parts) A. None of these. B. O C. D. 1 E. F. -s2 2. Find L(1) A. 1 B. None of these. C. 1 D.-s E. 0

Solution

a. L{t}

L{t} = ∫₀⁰⁰e^{-st}t

Integrating by parts  ∫udv/dt = uv - ∫vdu/dt where u = t and dv/dt = e^{-st} and v = \frac{e^{-st}}{-s} and du/dt = dt/dt = 1

So, ∫₀⁰⁰udv/dt = uv - ∫₀⁰⁰vdu/dt w

So,  ∫₀⁰⁰e^{-st}t =  [\frac{te^{-st}}{-s}]₀⁰⁰ -  ∫₀⁰⁰ \frac{e^{-st}}{-s}

∫₀⁰⁰e^{-st}t =  [\frac{te^{-st}}{-s}]₀⁰⁰ -  ∫₀⁰⁰ \frac{e^{-st}}{-s}

= -1/s(∞exp(-∞s) - 0 × exp(-0s)) + \frac{1}{s} [\frac{e^{-st} }{-s}]₀⁰⁰

= -1/s[(∞exp(-∞) - 0 × exp(0)] - 1/s²[exp(-∞s) - exp(-0s)]

= -1/s[(∞ × 0 - 0 × 1] - 1/s²[exp(-∞) - exp(-0)]

= -1/s[(0 - 0] - 1/s²[0 - 1]

= -1/s[(0] - 1/s²[- 1]

= 0 + 1/s²

= 1/s²

L{t} = 1/s²

b. L{1}

L{1} = ∫₀⁰⁰e^{-st}1

= [\frac{e^{-st} }{-s}]₀⁰⁰

= -1/s[exp(-∞s) - exp(-0s)]

= -1/s[exp(-∞) - exp(-0)]

= -1/s[0 - 1]

= -1/s(-1)

= 1/s

L{1} = 1/s

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I believe it is (5,16)
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honestly im not sure if this is right just my best educated guess sorry.
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Zane
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3 years ago
Where are 8 times as many Males as females on the maths course at university. What fraction of the course are male? Give your
irga5000 [103]

Answer:

equal apart from each other

Step-by-step explanation:

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