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attashe74 [19]
3 years ago
5

Which refers to the sum of all the forces that act upon an object?

Physics
1 answer:
ElenaW [278]3 years ago
4 0

Answer:

Net force refers to the sum of all the forces that act upon an object.

Explanation:

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(OUR
natta225 [31]

George's speed  per second is 76.92 m/s

George's velocity in meters per second was 38.46 m/s (North)

<u>Explanation:</u>

When dividing the total distance covered by object by time, we get the value for average speed.

\text { speed }=\frac{\text {distance}}{\text {time}}

<u>Given:</u>

t = 13 seconds

Calculate the distance without consideration of motion’s direction. So, the distance walks 750 m north first, and then turn around walks 250 m south, so the total distance covered is

d = 750 + 250 = 1000 meters

To find the rate per second, simply divide the distance by the time.

\text { speed }=\frac{1000}{13}=76.92 \mathrm{m} / \mathrm{s}

In given case, the students walks 750 m north first, and then turn around walk 250 m south. The displacement is the distance in a straight line between the initial and final position: therefore, in this case, the displacement is

d = 750 (north) - 250 (south) = 500 m (north)

The time taken is t = 13 s

So, the average velocity is\text {velocity}=\frac{500}{13}=38.46 \mathrm{m} / \mathrm{s} (North)

And the direction is north (the same as the displacement).

3 0
4 years ago
Explain why a moving object cannot come to a stop instantly in zero seconds
sineoko [7]
Well because it has momentum and it needs to be slowed down.
7 0
3 years ago
Read 2 more answers
Akito pushes a wheelbarrow with 800 W of power. How much work is required to get the wheelbarrow across the yard in 12 s? Round
Oxana [17]

Answer:

9600

Explanation:

5 0
3 years ago
Read 2 more answers
If this wave has frequency of 15 hz. what is the wavelength of that wave ?
Aneli [31]
Do you have any other information? Like the velocity of the wave?
4 0
4 years ago
Monochromatic light falling on two very narrow slits 0.048mm apart. Successive fringes on a screen 5.00m away are 6.5cm apart ne
tino4ka555 [31]

Answer:

λ = 5.85 x 10⁻⁷ m = 585 nm

f = 5.13 x 10¹⁴ Hz

Explanation:

We will use Young's Double Slit Experiment's Formula here:

Y = \frac{\lambda L}{d}\\\\\lambda = \frac{Yd}{L}

where,

λ = wavelength = ?

Y = Fringe Spacing = 6.5 cm = 0.065 m

d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m

L = screen distance = 5 m

Therefore,

\lambda = \frac{(0.065\ m)(4.8\ x\ 10^{-5}\ m)}{5\ m}

<u>λ = 5.85 x 10⁻⁷ m = 585 nm</u>

Now, the frequency can be given as:

f = \frac{c}{\lambda}

where,

f = frequency = ?

c = speed of light = 3 x 10⁸ m/s

Therefore,

f = \frac{3\ x\ 10^8\ m/s}{5.85\ x\ 10^{-7}\ m}\\\\

<u>f = 5.13 x 10¹⁴ Hz</u>

5 0
3 years ago
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